MariaDB 在 JSON 中跨数组更新 json 属性

Question

Goal I have a json column in my table which I want to update in MariaDB 10.3.18.

CREATE TABLE IF NOT EXISTS `json_data` (
  `name` VARCHAR(255),
  `config_json` MEDIUMTEXT(10000)
);

config_json 字段具有这样的值。

{
    "one": {
        "filters": [
            {
                "type": "campaign_categories_5",
                "title": "Title1"
            }
        ],
        "value1": "one",
        "containers": [],
        "combined": false
    },
    "description": "",
    "columns": [
        {
            "dataType": "STRING",
            "title": "Title1"
        },
        {
            "dataType": "STRING",
            "title": "Title2"
        },
        {
            "dataType": "STRING",
            "title": "Title3"
        },
        {
            "dataType": "STRING",
            "title": "Title1"
        }
    ]
}

我正在尝试通过将路径 column[*].title 中 config_json 的属性 "title" 替换为值 "Title1" 来更新 table 中的每个条目"Updated Title1"、"Title2" 与 "Updated Title2" 和 "Title3" 与 "Updated Title3"。更新后的 json 应该是这样的

{
    "one": {
        "filters": [
            {
                "type": "campaign_categories_5",
                "title": "Title1"
            }
        ],
        "value1": "one",
        "containers": [],
        "combined": false
    },
    "description": "",
    "columns": [
        {
            "dataType": "STRING",
            "title": "Updated Title1"
        },
        {
            "dataType": "STRING",
            "title": "Updated Title2"
        },
        {
            "dataType": "STRING",
            "title": "Updated Title3"
        },
        {
            "dataType": "STRING",
            "title": "Updated Title1"
        }
    ]
}

正如您在上面看到的，我不应该更改其他路径中的标题属性。我正在尝试这个

drop FUNCTION  if EXISTS modify_json;
create FUNCTION modify_json(myvar json)
returns json
deterministic
begin

    SET @i = 0;
    SET @len = JSON_LENGTH(myvar, '$.columns');
    while i < @len do
        IF JSON_CONTAINS(myvar, '"Title1"', concat('$.columns[', i, '].title')) THEN
            set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), '"Updated Title1"');
        END IF;
        IF JSON_CONTAINS(myvar, '"Title2"', concat('$.columns[', i, '].title')) THEN
            set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), '"Updated Title2"');
        END IF;
        IF JSON_CONTAINS(myvar, '"Title3"', concat('$.columns[', i, '].title')) THEN
            set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), '"Updated Title3"');
        END IF;
        set i = i + 1;
    end while;
    return myvar;
end;

update config_suite_reports_element set config_json = modify_json(config_json)
where json_contains_path(config_json, 'one', '$.columns[*].title');

但我收到以下错误

Error occurred during SQL script execution

Reason:
SQL Error [1064] [42000]: (conn=5434951) You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 6

Answer 1

我发现了问题。 1.定界符 2. 最新mariaDB 10.3

变量命名规则

DROP FUNCTION IF EXISTS func;
DELIMITER //

CREATE FUNCTION func(myvar json) RETURNS json DETERMINISTIC
BEGIN
  DECLARE i TINYINT;
  DECLARE len TINYINT;
  SET i = 0;
  SET len = JSON_LENGTH(myvar, '$.columns');
  while i < len do
    IF JSON_CONTAINS(myvar, '"Title1"', concat('$.columns[', i, '].title')) THEN
        set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), 'Updated Title1');
    ELSEIF JSON_CONTAINS(myvar, '"Title2"', concat('$.columns[', i, '].title')) THEN
        set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), 'Updated Title2');
    ELSEIF JSON_CONTAINS(myvar, '"Title3"', concat('$.columns[', i, '].title')) THEN
        set myvar = json_replace(myvar, concat('$.columns[', i, '].title'), 'Updated Title3');
    END IF;
    set i = i + 1;
  end while;
  RETURN myvar;
END 

//

DELIMITER ;

谢谢@BillKarwin

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