Sanic

Question

如果我将路线定义为（仅代码的相关部分）：

...
@app.get("brawlstats/endpoint:path>")
...

我尝试访问路由 /brawlstats/rankings/global/brawlers/16000001?limit=200，它在问号处中断。我希望端点包括整个 url。我如何让它包含整个路径？

Answer 1

? 之后的所有内容都被视为 query string 的一部分。你的 endpoint 代表 path after /brawlstats.

由于 endpoint 和 limit 参数分开，您可以使用此示例检索两者：

from sanic import Sanic
from sanic.response import text

app = Sanic()


@app.get('/brawlstats/<endpoint:path>')
async def brawlstats(request, endpoint):

    # endpoint is set to part after '/brawlstats'.
    # limit query arg is converted to integer or 0 if it's not set.
    limit = int(request.args.get('limit', 0))

    if endpoint == 'rankings/global/brawlers/16000001' and limit > 0:
        return text('Success', 200)

    return text('Bad request', 400)

if __name__ == "__main__":
    app.run(host="127.0.0.1", port=8000)

Sanic - 端点的路径类型不包含查询参数

Sanic - path type of endpoint doesn't include query arguments

python

routing