通过嵌套计算 ElasticSearch 中的搜索结果 属性
Counting search results in ElasticSearch by a nested property
这是一个带有嵌套 属性 的模式。
{
"dynamic": "strict",
"properties" : {
"Id" : {
"type": "integer"
},
"Name_en" : {
"type": "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"normalizer": "cloudbuy_normalizer_alphanumeric"
},
"text" : {
"type" : "text",
"analyzer": "english"
}
}
},
"Menus" : {
"type" : "nested",
"properties" : {
"Id" : {
"type" : "integer"
},
"Name" : {
"type" : "keyword",
"normalizer": "normalizer_alphanumeric"
},
"AncestorsIds" : {
"type" : "integer"
}
}
}
}
}
这是一份文件。
{
"Id": 12781279
"Name": "Thing of purpose made to fit",
"Menus": [
{
"Id": -571057,
"Name": "Top level menu",
"AncestorsIds": [
-571057
]
}
,
{
"Id": 1022313,
"Name": "Other",
"AncestorsIds": [
-571057
,
1022313
]
}
]
}
对于任何给定的查询,我需要一个包含两列的列表:Menu.Id 和结果集中在 Menus
数组中具有 Menu.Id 的文档数。
怎么样?
(是否有任何关于 aggs
的文档不是不可理解的?)
@Richard,这个查询符合您的需要吗?
POST yourindex/_search
{
"_source": "false",
"aggs":{
"menus": {
"nested": {
"path": "Menus"
},
"aggs":{
"menu_aggregation": {
"terms": {
"field": "Menus.Id",
"size": 10
}
}
}
}
}
输出:
"aggregations": {
"menus": {
"doc_count": 2,
"menu_aggregation": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": -571057,
"doc_count": 1
},
{
"key": 1022313,
"doc_count": 1
}
]
}
}
这里我们指定了一个嵌套路径,然后在菜单Ids上聚合。
您可以查看此文档页面:https://www.elastic.co/guide/en/elasticsearch/reference/current/search-aggregations-bucket-nested-aggregation.html
这是一个带有嵌套 属性 的模式。
{
"dynamic": "strict",
"properties" : {
"Id" : {
"type": "integer"
},
"Name_en" : {
"type": "text",
"fields" : {
"keyword" : {
"type" : "keyword",
"normalizer": "cloudbuy_normalizer_alphanumeric"
},
"text" : {
"type" : "text",
"analyzer": "english"
}
}
},
"Menus" : {
"type" : "nested",
"properties" : {
"Id" : {
"type" : "integer"
},
"Name" : {
"type" : "keyword",
"normalizer": "normalizer_alphanumeric"
},
"AncestorsIds" : {
"type" : "integer"
}
}
}
}
}
这是一份文件。
{
"Id": 12781279
"Name": "Thing of purpose made to fit",
"Menus": [
{
"Id": -571057,
"Name": "Top level menu",
"AncestorsIds": [
-571057
]
}
,
{
"Id": 1022313,
"Name": "Other",
"AncestorsIds": [
-571057
,
1022313
]
}
]
}
对于任何给定的查询,我需要一个包含两列的列表:Menu.Id 和结果集中在 Menus
数组中具有 Menu.Id 的文档数。
怎么样?
(是否有任何关于 aggs
的文档不是不可理解的?)
@Richard,这个查询符合您的需要吗?
POST yourindex/_search
{
"_source": "false",
"aggs":{
"menus": {
"nested": {
"path": "Menus"
},
"aggs":{
"menu_aggregation": {
"terms": {
"field": "Menus.Id",
"size": 10
}
}
}
}
}
输出:
"aggregations": {
"menus": {
"doc_count": 2,
"menu_aggregation": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": -571057,
"doc_count": 1
},
{
"key": 1022313,
"doc_count": 1
}
]
}
}
这里我们指定了一个嵌套路径,然后在菜单Ids上聚合。 您可以查看此文档页面:https://www.elastic.co/guide/en/elasticsearch/reference/current/search-aggregations-bucket-nested-aggregation.html