Spring 涉及 COUNT() 和 LOWER() 的 JPA 查询

Question

我是 Spring JPA/JPQL 的新手，但尝试复制以下 MySQL 查询，但没有取得太大成功。我们无法克服看起来像是语法错误的问题，它看起来是试图混合使用 COUNT() 和 LOWER() 的函数。

MySQL（有效）是：

select lower(sdetail_cvalue) as stringValue, 
count(lower(sdetail_cvalue)) as stringValueCount 
from <someTable>
where sdetail_cfield not like <someValue>
and sdetail_cfield not like <someOtherValue>
and sdetail_cfield not like <someOtherOtherValue>
group by stringValue
order by stringValueCount desc

我正在尝试的相应 JPQL 是

SELECT new <searchResult> 
(lower(sd.searchText) as searchText, 
COUNT(lower(sd.searchText)) as searchTextOccurrenceCount) 
FROM <someTable> sd 
WHERE sd.searchType not like <someValue> 
AND sd.searchType not like <someOtherValue> 
AND sd.searchType not like <someOtherOtherValue> 
GROUP BY searchText 
ORDER BY searchTextOccurrenceCount DESC

但在执行时得到以下错误信息

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: expecting CLOSE, found '(' near line 1, column 128 [SELECT new <REDACTED> (lower(sd.searchText) as searchText, COUNT(lower(sd.searchText)) as searchTextOccurrenceCount) FROM <someTable> sd WHERE sd.searchType not like <someValue> AND sd.searchType not like <someOtherValue> AND sd.searchType not like <someOtherOtherValue> GROUP BY searchText ORDER BY searchTextOccurrenceCount DESC]

我已经编辑了上面的一些内容，但列号（即 128）指的是 'lower' 和 'sd.'

之间的“（”

我们尝试了多种方法来解构查询以查明问题，这似乎是我们使用的是复合 COUNT(LOWER()) 构造。有没有人有使用 JPQL 成功实现此类事情的示例？...在此先感谢。

Answer 1

您是否考虑过将 nativeQuery = true 添加到您的 @Query 注释中？

Spring 涉及 COUNT() 和 LOWER() 的 JPA 查询

Spring JPA query involving COUNT() and LOWER()

mysql

spring

jpql

spring-data-jpa