根据 mysql 中的特定列数据过滤数据
Filter data based on specific column data in mysql
我的数据库中有以下表格。
Table: actor_action
actor_id | time | monday_action_id | tuesday_action_id | .... | friday_action_id
1 1 2 1 3
1 2 3 4 1
2 1 1 5 4
Table:动作
action_id | action_name | action_type | action_group_name
1 A1 single -
2 X2 multiple X_GROUP
3 B1 single -
4 X1 multiple X_GROUP
5 Y1 multiple Y_GROUP
我想查询给定 actor_id 的以下详细信息(例如:actor_id = 1)。在这里,如您所见,如果 action_type
是“multiple”,我想 select action_group_name
而不是 action_name
。
预期输出:-
actor_id | time | monday_name | tuesday_name | .... | friday_name
1 1 X_GROUP A1 B1
1 2 B1 X_GROUP A1
目前我有以下查询,其中 select 只是操作名称。
SELECT a1.action_name AS monday_name,
a2.action_name AS tuesday_name,
a3.action_name AS wednesday_name,
a4.action_name AS thursday_name,
a5.action_name AS friday_name,
act.time AS time
FROM actor_action act
LEFT JOIN action a1 ON ct.monday_action_id=a1.action_id
LEFT JOIN action a2 ON ct.tuesday_action_id=a2.action_id
LEFT JOIN action a3 ON ct.wednesday_action_id=a3.action_id
LEFT JOIN action a4 ON ct.thursday_action_id=a4.action_id
LEFT JOIN action a5 ON ct.friday_action_id=a5.action_id
WHERE act.actor_id = ?
我如何编写一个查询来执行我上面提到的过滤。
您只需替换每个单独的列选择,例如
a1.action_name AS monday_name
使用适当的 CASE
表达式:
CASE WHEN a1.action_type = 'multiple' THEN a1.action_group_name
ELSE a1.action_name
END AS monday_name
输出(基于您的示例数据)
monday_name tuesday_name friday_name time
X_GROUP A1 B1 1
B1 X_GROUP A1 2
请注意,根据查询中的 table 别名,此列的 table 别名应为 a1
,而不是 s1
。
我的数据库中有以下表格。
Table: actor_action
actor_id | time | monday_action_id | tuesday_action_id | .... | friday_action_id
1 1 2 1 3
1 2 3 4 1
2 1 1 5 4
Table:动作
action_id | action_name | action_type | action_group_name
1 A1 single -
2 X2 multiple X_GROUP
3 B1 single -
4 X1 multiple X_GROUP
5 Y1 multiple Y_GROUP
我想查询给定 actor_id 的以下详细信息(例如:actor_id = 1)。在这里,如您所见,如果 action_type
是“multiple”,我想 select action_group_name
而不是 action_name
。
预期输出:-
actor_id | time | monday_name | tuesday_name | .... | friday_name
1 1 X_GROUP A1 B1
1 2 B1 X_GROUP A1
目前我有以下查询,其中 select 只是操作名称。
SELECT a1.action_name AS monday_name,
a2.action_name AS tuesday_name,
a3.action_name AS wednesday_name,
a4.action_name AS thursday_name,
a5.action_name AS friday_name,
act.time AS time
FROM actor_action act
LEFT JOIN action a1 ON ct.monday_action_id=a1.action_id
LEFT JOIN action a2 ON ct.tuesday_action_id=a2.action_id
LEFT JOIN action a3 ON ct.wednesday_action_id=a3.action_id
LEFT JOIN action a4 ON ct.thursday_action_id=a4.action_id
LEFT JOIN action a5 ON ct.friday_action_id=a5.action_id
WHERE act.actor_id = ?
我如何编写一个查询来执行我上面提到的过滤。
您只需替换每个单独的列选择,例如
a1.action_name AS monday_name
使用适当的 CASE
表达式:
CASE WHEN a1.action_type = 'multiple' THEN a1.action_group_name
ELSE a1.action_name
END AS monday_name
输出(基于您的示例数据)
monday_name tuesday_name friday_name time
X_GROUP A1 B1 1
B1 X_GROUP A1 2
请注意,根据查询中的 table 别名,此列的 table 别名应为 a1
,而不是 s1
。