使用 ggplotly() 时反转图例顺序
Reverse the legend order when using ggplotly()
我想颠倒水平条形图图例的顺序。将 guides(fill = guide_legend(reverse = TRUE))
添加到 ggplot
时效果很好(见第二个图)。但是,在应用 ggplotly()
之后,图例再次采用默认顺序。
如何在不改变条形顺序的情况下反转plotly
图例的顺序?
library(ggplot2)
library(dplyr)
data(mtcars)
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p1
p2 <- p1 + guides(fill = guide_legend(reverse = TRUE))
p2
plotly::ggplotly(p2)
一个简单的解决方案是定义因子变量水平的顺序 am
:
library(ggplot2)
library(dplyr)
data(mtcars)
df <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(as.character(am), levels = c("1", "0")))
head(df)
p1 <- df %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p1
plotly::ggplotly(p1)
当您调用 ggplotly 时,它实际上只是创建一个列表并在该列表上调用一个函数。
所以如果你省去了那个中间步骤,你可以直接修改列表。因此,修改绘图输出。
library(ggplot2)
library(dplyr)
data(mtcars)
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
html_plot <- ggplotly(p1)
replace_1 <- html_plot[["x"]][["data"]][[2]]
replace_2 <- html_plot[["x"]][["data"]][[1]]
html_plot[["x"]][["data"]][[1]] <- replace_1
html_plot[["x"]][["data"]][[2]] <- replace_2
html_plot
plot output
在@Zac Garland 的精彩回答中添加一个适用于任意长度图例的解决方案:
library(ggplot2)
library(dplyr)
reverse_legend_labels <- function(plotly_plot) {
n_labels <- length(plotly_plot$x$data)
plotly_plot$x$data[1:n_labels] <- plotly_plot$x$data[n_labels:1]
plotly_plot
}
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p2 <- mtcars %>%
count(am, cyl) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(am, n, fill = cyl)) +
geom_col(position = "dodge") +
coord_flip()
p1 %>%
plotly::ggplotly() %>%
reverse_legend_labels()
p2 %>%
plotly::ggplotly() %>%
reverse_legend_labels()
我想颠倒水平条形图图例的顺序。将 guides(fill = guide_legend(reverse = TRUE))
添加到 ggplot
时效果很好(见第二个图)。但是,在应用 ggplotly()
之后,图例再次采用默认顺序。
如何在不改变条形顺序的情况下反转plotly
图例的顺序?
library(ggplot2)
library(dplyr)
data(mtcars)
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p1
p2 <- p1 + guides(fill = guide_legend(reverse = TRUE))
p2
plotly::ggplotly(p2)
一个简单的解决方案是定义因子变量水平的顺序 am
:
library(ggplot2)
library(dplyr)
data(mtcars)
df <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(as.character(am), levels = c("1", "0")))
head(df)
p1 <- df %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p1
plotly::ggplotly(p1)
当您调用 ggplotly 时,它实际上只是创建一个列表并在该列表上调用一个函数。
所以如果你省去了那个中间步骤,你可以直接修改列表。因此,修改绘图输出。
library(ggplot2)
library(dplyr)
data(mtcars)
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
html_plot <- ggplotly(p1)
replace_1 <- html_plot[["x"]][["data"]][[2]]
replace_2 <- html_plot[["x"]][["data"]][[1]]
html_plot[["x"]][["data"]][[1]] <- replace_1
html_plot[["x"]][["data"]][[2]] <- replace_2
html_plot
plot output
在@Zac Garland 的精彩回答中添加一个适用于任意长度图例的解决方案:
library(ggplot2)
library(dplyr)
reverse_legend_labels <- function(plotly_plot) {
n_labels <- length(plotly_plot$x$data)
plotly_plot$x$data[1:n_labels] <- plotly_plot$x$data[n_labels:1]
plotly_plot
}
p1 <- mtcars %>%
count(cyl, am) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(cyl, n, fill = am)) +
geom_col(position = "dodge") +
coord_flip()
p2 <- mtcars %>%
count(am, cyl) %>%
mutate(cyl = factor(cyl), am = factor(am)) %>%
ggplot(aes(am, n, fill = cyl)) +
geom_col(position = "dodge") +
coord_flip()
p1 %>%
plotly::ggplotly() %>%
reverse_legend_labels()
p2 %>%
plotly::ggplotly() %>%
reverse_legend_labels()