我在 Pattern.compile() 和 .matcher() 中传递变量但没有获得所需的输出
I am passing variables in Pattern.compile() and .matcher() but not getting required output
我编写了一个程序,要求用户提供目标字符串和要在其中搜索的模式。它旨在找到匹配模式的位置以及它在目标字符串中出现的次数。但它总是显示没有找到模式,即使模式存在于目标字符串中。
我已经为它写了一个函数searchPattern()
。
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main
{
private static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
String pattern,target;
System.out.println("Enter Target String: ");
pattern = sc.nextLine();
System.out.println("Enter pattern to be searched: ");
target = sc.nextLine();
searchPattern(pattern,target);
}
public static void searchPattern(String pattern,String target)
{
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(target);
int count = 0;
//if(!m.find())return;
while (m.find())
{
count ++;
System.out.println(m.start() + "--" + m.end() + "--" + m.group());
}
if (count == 0)
System.out.println("Your pattern was not found in the target string");
else
System.out.println("Total occurrences of 'ab' are" + count);
}
}
它给出以下输出:
Enter Target String:
ababbab
Enter pattern to be searched:
ab
Your pattern was not found in the target string
即使 'ab' 出现在目标字符串中,为什么此代码不起作用
您将目标和模式存储在错误的变量中
private static Scanner sc = new Scanner(System.in);
public static void main(String[] args) {
String pattern, target;
System.out.println("Enter Target String: ");
target = sc.nextLine();
System.out.println("Enter pattern to be searched: ");
pattern = sc.nextLine();
searchPattern(pattern, target);
}
public static void searchPattern(String pattern, String target) {
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(target);
int count = 0;
while (m.find()) {
count++;
System.out.println(m.start() + "--" + m.end() + "--" + m.group());
}
if (count == 0) {
System.out.println("Your pattern was not found in the target string");
} else {
System.out.println("Total occurrences of " + pattern + " are" + count);
}
}
我编写了一个程序,要求用户提供目标字符串和要在其中搜索的模式。它旨在找到匹配模式的位置以及它在目标字符串中出现的次数。但它总是显示没有找到模式,即使模式存在于目标字符串中。
我已经为它写了一个函数searchPattern()
。
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main
{
private static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
String pattern,target;
System.out.println("Enter Target String: ");
pattern = sc.nextLine();
System.out.println("Enter pattern to be searched: ");
target = sc.nextLine();
searchPattern(pattern,target);
}
public static void searchPattern(String pattern,String target)
{
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(target);
int count = 0;
//if(!m.find())return;
while (m.find())
{
count ++;
System.out.println(m.start() + "--" + m.end() + "--" + m.group());
}
if (count == 0)
System.out.println("Your pattern was not found in the target string");
else
System.out.println("Total occurrences of 'ab' are" + count);
}
}
它给出以下输出:
Enter Target String:
ababbab
Enter pattern to be searched:
ab
Your pattern was not found in the target string
即使 'ab' 出现在目标字符串中,为什么此代码不起作用
您将目标和模式存储在错误的变量中
private static Scanner sc = new Scanner(System.in);
public static void main(String[] args) {
String pattern, target;
System.out.println("Enter Target String: ");
target = sc.nextLine();
System.out.println("Enter pattern to be searched: ");
pattern = sc.nextLine();
searchPattern(pattern, target);
}
public static void searchPattern(String pattern, String target) {
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(target);
int count = 0;
while (m.find()) {
count++;
System.out.println(m.start() + "--" + m.end() + "--" + m.group());
}
if (count == 0) {
System.out.println("Your pattern was not found in the target string");
} else {
System.out.println("Total occurrences of " + pattern + " are" + count);
}
}