indexOf() 在数组中找不到值

Question

基于此 post，我正在研究概念证明，以通过 Google 表单捕获项目请求，通过电子邮件发送以供批准，并将批准结果发回相应的行在 Google sheet 中。该行是从数组中搜索的，使用时间戳作为键。

我面临两个挑战：首先，数组中的时间戳采用不同的格式，有时相差 1 秒。我通过调整格式以匹配数组值的外观和运行如果第一次时间戳搜索失败则进行第二次搜索来对此进行调整。我希望这是万无一失的，但如果有更好的方法，请告诉我。我不明白为什么有时会有 1 秒的差异。

我遇到了 第二个挑战：我根本无法在数组 中成功搜索时间戳。 indexOf() 始终 returns 值为 -1.

将不胜感激任何帮助。需要的话请详细一点，我是新手

这是我的代码：

function sendEmail(e) {
  // Response columns: Timestamp    Requester Email Item    Cost
  var email = e.namedValues["Requester Email"];
  var item = e.namedValues["Item"];
  var cost = e.namedValues["Cost"];
  var timestamp = e.namedValues["Timestamp"];

  var url = ScriptApp.getService().getUrl();

  // Enhancement: include timestamp to coordinate response  
  var options = '?approval=%APPROVE%&timestamp=%TIMESTAMP%&reply=%EMAIL%'
         .replace("%TIMESTAMP%",encodeURIComponent(e.namedValues["Timestamp"]))
         .replace("%EMAIL%",e.namedValues["Requester Email"])         
  var approve = url+options.replace("%APPROVE%","Approved"); 
  var reject = url+options.replace("%APPROVE%","Rejected");

  var html = "<body>"+
                "<h2>Please review</h2><br />"+
                "Request from: " + email + "<br />"+
                "For: "+item +", at a cost of: $" + cost + "<br /><br />"+ 
                "<a href="+ approve +">Approve</a><br />"+
                "<a href="+ reject +">Reject</a><br />"+
             "</body>";

  MailApp.sendEmail(Session.getEffectiveUser().getEmail(),
                    "Approval Request", 
                    "Requires html",
                    {htmlBody: html});  
}


function doGet(e) {

  var answer = (e.parameter.approval === 'Approved') ? 'Buy it!' : 'Not this time, Keep saving'; 
  var timestamp = e.parameter.timestamp;
  var newtimestamp = Utilities.formatDate(new Date(timestamp), "GMT+8", "EEE MMM dd yyyy HH:mm:ss 'GMT+0800 (SGT)'");  //reformat timestamp to match the ones in the data array
  var approvalCol = 5;

  MailApp.sendEmail(e.parameter.reply, "Purchase Request", 
                    "Your manager said: "+ answer);   

  // Update approval status back to the sheet
  var wsID = "<myworksheetID>";
  var sheet = SpreadsheetApp.openById(wsID).getSheetByName("Requests");
  var data = sheet.getDataRange().getValues();

  var oneColArray = new Array();
  for(i=0;i<data.length;++i){
     oneColArray.push(data[i][0]); // taking index 0 means I'll get column A of each row and put it in the new array
  }

  var row = oneColArray.indexOf(newtimestamp);

  Logger.log("\ntimestamp: " + timestamp + "\n\n" + "newtimestamp: " + newtimestamp + "\n\n" + "oneColArray: \n" + oneColArray);

  if (row < 0) {                                     //not found
    //Lower timestamp by 1 second. Sometimes there is a 1-second difference than the one in the array. I don't know why
    var dateString = Utilities.formatDate(new Date(timestamp), "GMT+8",'EEE, d MMM yyyy HH:mm:ss');
    var date = new Date(dateString);
    var revisedtimestamp = new Date((date.getTime() - (1/(24*60*60)*1000)));

    // now search again using the adjusted timestamp
    var row = oneColArray.indexOf(revisedtimestamp); 

    if (row < 0) {
       Logger.log("\ntimestamp: " + timestamp + "\n\n" + "newtimestamp: " + newtimestamp + "\n\n" + "oneColArray: \n" + oneColArray + "\n\n" + "revisedtimestamp: " + revisedtimestamp);
       throw new Error ("Request not found in list.");
    } else {
    sheet.getRange(row + 1, approvalCol).setValue(e.parameter.approval);
    }
  } else {
    sheet.getRange(row + 1, approvalCol).setValue(e.parameter.approval);
    }
}

Answer 1

我找到了基于此 post 的解决方案。

我更改了这一行：

var row = oneColArray.indexOf(newtimestamp);

为此将数组转换为字符串，indexOf() return是它找到第一次出现时间戳的起点。根据 return 值，我刚刚计算出它在工作表中的行数：

var row = oneColArray.join().indexOf(newtimestamp);

我更喜欢的另一个变体是循环遍历数据数组的时间戳列，在每个循环中，在执行 indexOf() 之前将值转换为字符串。我只需要将 1 添加到 [i] 即可获得工作表中的实际行。

for (var i = 0; i < data.length; ++i) {
       var row = data[i][0].toString().indexOf(newtimestamp);
    if (row > -1) {
      var a = i;
      break;
    }
  }

indexOf() 在数组中找不到值

indexOf() doesn't find the value in array

arrays

timestamp

indexof