如何根据 Javascript 的值将我的数组拆分为多个数组？

Question

我有一个数组，我想根据值'Finished'将它拆分成多个数组，当我找到它时，我拆分数组。

我的代码是：

var input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', '├─BROKEN─url1HTTP_404' , 'ok', 'urlok', 'Finished', 
            'urlGettingF2', '├─BROKEN─url1HTTP_404','├─BROKEN─url21HTTP_404', 'Finished',
            'urlGettingF3', '├─BROKEN─url3HTTP_404','├─BROKEN─url213HTTP_404', 'Finished'
];

function chunkArray(array, size) {
  let result = []
  for (value of array) {
    let lastArray = result[result.length - 1]
    if (!lastArray || lastArray.length == size) {
      result.push([value])
    } else {
      lastArray.push(value)
    }
  }
  return result
}

const x = input.findIndex(element => element.indexOf('Finished') > -1)
console.log(chunkArray(input, x + 1));

当我运行我得到 :

但我希望结果是：

[["urlGettingF", "├─BROKEN─aquaHTTP_404", "├─BROKEN─url1HTTP_404", "ok", "urlok", "Finished"], ["urlGettingF2", "├─BROKEN─url1HTTP_404", "├─BROKEN─url21HTTP_404", "Finished"], ["urlGettingF3", "├─BROKEN─url3HTTP_404", "├─BROKEN─url213HTTP_404", "Finished"]]

当我找到Finished时，我根据她的索引拆分我的数组，你可以在jsbin中看到我的代码 https://jsbin.com/benozuyutu/1/edit?js,console

我该如何解决？

Answer 1

您可能会找到 Finished 和 .reduce 的所有匹配项，然后通过 .slice 在找到的索引处对每个匹配项创建一个新数组：

var input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', '├─BROKEN─url1HTTP_404', 'ok', 'urlok', 'Finished',
  'urlGettingF2', '├─BROKEN─url1HTTP_404', '├─BROKEN─url21HTTP_404', 'Finished',
  'urlGettingF3', '├─BROKEN─url3HTTP_404', '├─BROKEN─url213HTTP_404', 'Finished'
];

const finishedIndicies = input.reduce((a, item, i) => {
  if (item === 'Finished') {
    a.push(i);
  }
  return a;
}, []);
const chunked = finishedIndicies.map(
  (sliceIndex, i, arr) => input.slice(arr[i - 1] === undefined ? 0 : arr[i - 1] + 1, sliceIndex + 1)
);
console.log(chunked);

Answer 2

var input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', '├─BROKEN─url1HTTP_404', 'ok', 'urlok', 'Finished',
  'urlGettingF2', '├─BROKEN─url1HTTP_404', '├─BROKEN─url21HTTP_404', 'Finished',
  'urlGettingF3', '├─BROKEN─url3HTTP_404', '├─BROKEN─url213HTTP_404', 'Finished'
];

function chunkArray(arr) {
  let result = [
    []
  ];
  let index = 0;
  arr.forEach((x, i) => {
    result[index].push(x);
    if ((i + 1) < arr.length && x.includes('Finished')) {
      index++;
      result[index] = [];
    }
  });
  return result
}
console.log(chunkArray(input));

Answer 3

var input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', '├─BROKEN─url1HTTP_404', 'ok', 'urlok', 'Finished', 'urlGettingF2', '├─BROKEN─url1HTTP_404', '├─BROKEN─url21HTTP_404', 'Finished', 'urlGettingF3', '├─BROKEN─url3HTTP_404', '├─BROKEN─url213HTTP_404', 'Finished']

const res = input
  .join(' ')
  .split('Finished')
  .map(item => item.split(' ').filter(item => item))
  .filter(item => item.length)
  .map(item => [...item, 'Finished'])
 
console.log(res)

Answer 4

您可以使用以下算法。

查找indexOf('Finished')
使用Array.splice函数获取index之前的值。 .splice 也更新现有数组。
执行上述操作直到 indexOf('Finished') > -1
最后，在output array

input array

let input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', '├─BROKEN─url1HTTP_404', 'ok', 'urlok', 'Finished',
  'urlGettingF2', '├─BROKEN─url1HTTP_404', '├─BROKEN─url21HTTP_404', 'Finished',
  'urlGettingF3', '├─BROKEN─url3HTTP_404', '├─BROKEN─url213HTTP_404', 'Finished'
];

let output = [];

while (true) {
  output.push(input.splice(0, input.indexOf('Finished') + 1));

  if (input.indexOf('Finished') === -1) {
    input.length && output.push(input); //to add all remaining values
    
    break;
  }
}

console.log(output);

Answer 5

您可以使用reduce方法。在 reduce 方法中，需要检查要查找的关键字是否存在，如果存在则推入新创建的数组。否则，我们将推入现有数组：

let keywordToFind = 'urlGettingF';

const result = input.reduce((a, c) => {
    (c.includes(keywordToFind)) ? a.push([c]) : a[a.length - 1].push(c); 
    return a;
}, []);

一个例子：

var input = ['urlGettingF', '├─BROKEN─aquaHTTP_404', 
   '├─BROKEN─url1HTTP_404', 'ok', 'urlok', 'Finished',
  'urlGettingF2', '├─BROKEN─url1HTTP_404', '├─BROKEN─url21HTTP_404', 'Finished',
  'urlGettingF3', '├─BROKEN─url3HTTP_404', '├─BROKEN─url213HTTP_404', 'Finished'
];


let keywordToFind = 'urlGettingF';
const result = input.reduce((a, c) => {
    (c.includes(keywordToFind)) ? a.push([c]) : a[a.length - 1].push(c);
    return a;
}, []);

console.log(result);

如何根据 Javascript 的值将我的数组拆分为多个数组？

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