ruby中如何将n维数组变成字符串？

Question

我有一个多维数组：

[
  [:C],
  [:C, [:C]],  
  [:C, [[:C]]],
  [:C, [:C, [:C]]],
  [:C, [:C, [:C, :C]]],  
  [:C, [:C, [:C, [:C]]]],
  [:C, [:C, [:C, [:C, :C]]]],
]

我需要将它翻译成这样的字符串：

"C C(C) C((C)) C(C(C)) C(C(CC)) C(C(CC)) C(C(C(C)))"

为清楚起见，这里是内部数组，每个数组都显示了其翻译后的字符串：

[:C]                       => "C"
[:C, [:C]]                 => "C(C)"
[:C, [[:C]]]               => "C((C))"
[:C, [:C, [:C]]]           => "C(C(C))"
[:C, [:C, [:C, :C]]]       => "C(C(CC))"
[:C, [:C, [:C, [:C]]]]     => "C(C(CC))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(C)))"

我试过使用展平和连接但我没有得到期望的结果。我想要带括号的它，这样它就可以很容易地确定。如果我使用 flatten 或 concat，我会得到 CCCCCCCCCCCCC。我想要带括号。

Answer 1

假设需求是这样的：

[:C]                       => "C"
[:C, [:C]]                 => "C(C)"
[:C, [[:C]]]               => "C(C)"
[:C, [:C, [:C]]]           => "C(C(C))"
[:C, [:C, [:C, :C]]]       => "C(C(CC))"
[:C, [:C, [:C, [:C]]]]     => "C(C(C(C)))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(CC)))"

这不是你的问题所说的，但在 D-Side 的评论中，我认为这就是你想要的：基本上，用花括号替换除了外部括号之外的所有括号，并删除外部括号和不需要的格式化。

def to_formatted_string(array)
  array.inspect.gsub(/^\[|\]$|[\:\,\s]/,"").gsub("[","(").gsub("]",")")
end

测试 = [ [：C]， [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]] ]

tests.each{|arr| puts "#{arr.inspect} => #{to_formatted_string(arr).inspect}"};false

给予

[:C] => "C"
[:C, [:C]] => "C(C)"
[:C, [[:C]]] => "C((C))"
[:C, [:C, [:C]]] => "C(C(C))"
[:C, [:C, [:C, :C]]] => "C(C(CC))"
[:C, [:C, [:C, [:C]]]] => "C(C(C(C)))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(CC)))"

Answer 2

一旦您注意到第一层和其他层使用不同的规则进行格式化，该算法就很简单了。所以为了清楚起见，我不得不使用两个不同的函数。除此之外，该算法是不言自明的。但即便如此，我还是尽可能清楚地评论了它。

data = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]],
       [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]],
       [:C, [:C, [:C, [:C, :C]]]]

def format_step(e) # Expects an array, since all the elements of data are arrays.
  e.map do |x| # So for each element, get the following
    if x.is_a?(Array)
      "(#{ format_step(x) })" # ...then call the same function on it
    else
      x.to_s # convert to string and return
    end
  end.join # this way map returns an array of strings here, join them
end

def reformat(data) # This rule is only for the first level and is a bit different
  data.map do |element| # For each element of the root array
    format_step(element) # do this
  end.join(' ') # ..and join the results with spaces
end

puts reformat(data)

Answer 3

您可以根据需要创建字符串，如下所示：

array = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]
array.inspect.gsub(/(\[|\]|:C)/, '[' => '(', ']' => ')',':C' => 'c')

控制台输出：

2.1.2-p95 :029 > array = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]
 => [[:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]] 
2.1.2-p95 :030 > array.inspect.gsub(/(\[|\]|:C)/, '[' => '(', ']' => ')',':C' => 'c')
 => "((c), (c, (c)), (c, ((c))), (c, (c, (c))), (c, (c, (c, c))), (c, (c, (c, (c)))), (c, (c, (c, (c, c)))))"

ruby中如何将n维数组变成字符串？

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