将 Django 的 RequestFactory() 方法设置为等于 'POST'

Question

示例视图函数：

def example_view(request):
    if request.method == "POST":

        print(request.session['Key'])

        return HttpResponse("Success")

测试视图的测试用例：

from django.contrib.sessions.backends.db import SessionStore
from django.test import RequestFactory, TestCase
from website.views import example_view

class ExampleTestCase(TestCase):

    def test_example(self):

        # Create request and session
        request = RequestFactory()
        request.session = SessionStore()

        request.session['Key'] = "Value"

        response = example_view(request)

        self.assertEquals(response.status_code, 200)

urls.py 文件以备不时之需：

urlpatterns = [    
    path('example', views.example_view, name="example_view"),
]

错误响应：

AttributeError: 'RequestFactory' object has no attribute 'method'

没有：

if request.method == 'POST':

这按预期工作。

如何设置 request.method 等于 post？

Answer 1

RequestFactory 给你一个工厂，而不是一个请求，要获得你必须调用工厂的请求，就像你对 Django 测试客户端所做的那样：

factory = RequestFactory()
request = factory.post('/your/view/url')
response = example_view(request)

将 Django 的 RequestFactory() 方法设置为等于 'POST'

Set Django's RequestFactory() method to equal 'POST'

django

django-views

django-testing

python-3.x

django-tests