变量在函数中运行时表示它为 False，但随后又恢复为 True

Question

我目前正在为一门课程制作井字游戏。一切进展顺利，但是，我遇到了障碍。当我想检查玩家是否获胜时，我遇到了问题，这是一个函数（称为 "game_over"）。当我运行游戏时，如果满足 "if" 语句，则显示 "game_on = False"。但是，一旦播放器 while 循环开始，它就会恢复为 True。因此游戏永远不会停止。

game_on = True
player_ready = False
game_finish = False
turn = "Player1"


# THE BOARD
line1 = ["|", "___" , "|", "___", "|","___","|"]
line2 = ["|", "___" , "|", "___", "|","___","|"]
line3 = ["|", "___" , "|", "___", "|","___","|"]

list1 = ''.join(line1)
list2 = ''.join(line2)
list3 = ''.join(line3)
print(list1)
print(list2)
print(list3)

# FUNCTIONS AND THE GAME
Player1_character = "x"

def game_over(player,character):

  if line1[1] == (f"_{character}_") and line1[3] == (f"_{character}_") and line1[5] == (f"_{character}_"):
    game_on = False
    print(f"Game Over, {player} won!game_on = {game_on}")
    return





def print_character(numbers,char):
    if numbers == 1:
        line1[1] = (f"_{char}_")

    if numbers == 2:
        line1[3] = (f"_{char}_")

    if numbers == 3:
        line1[5] = (f"_{char}_")

    if numbers == 4:
        line2[1] = (f"_{char}_")

    if numbers == 5:
        line2[3] = (f"_{char}_")

    if numbers == 6:
        line2[5] = (f"_{char}_")

    if numbers == 7:
        line3[1] = (f"_{char}_")

    if numbers == 8:
        line3[3] = (f"_{char}_")

    if numbers == 9:
        line3[5] = (f"_{char}_")

    list1 = ''.join(line1)
    list2 = ''.join(line2)
    list3 = ''.join(line3)
    print(list1)
    print(list2)
    print(list3)




section = 0
# Tutorial Goes Here
while game_on == True:
    # Selecting Players
    while player_ready == False:
        Player1_character = ""
        Player1_character = input("Player1 choose your character 'x' or 'o': ")
        Player2_character = "|"

        if Player1_character == "x":
            Player2_character = "o"
        elif Player1_character == "o":
            Player2_character = "x"

        print(f"Player1 = {Player1_character} ||| Player2 = {Player2_character}")
        print("LETS BEGIN!!!\n")
        player_ready = True

    #Starting game:
    while turn == "Player1":
        section = int(input(f"Player1's Turn: \nSelect where you want to put your '{Player1_character}'(1-9){game_on}: "))
        print_character(section, Player1_character)

        if game_on == False:
          break

        turn = "Player2"



    while turn == "Player2":
        section = int(input(f"Player2's Turn: \nSelect where you want to put your '{Player2_character}'(1-9){game_on}: "))
        print_character(section, Player2_character)
        game_over("Player2",Player2_character)
        if game_on == False:
          break
        turn = "Player1"

Answer 1

请参阅 the rules for using global variables in functions 上的 Python 编程常见问题解答。

In Python, variables that are only referenced inside a function are implicitly global. If a variable is assigned a value anywhere within the function’s body, it’s assumed to be a local unless explicitly declared as global.

变量在函数中运行时表示它为 False，但随后又恢复为 True

Variable says it is False when run in the function, but then it reverts back to True

tic-tac-toe

python-3.x

变量在函数中 运行 时表示它为 False，但随后又恢复为 True

Variable says it is False when run in the function, but then it reverts back to True

tic-tac-toe

python-3.x

变量在函数中运行时表示它为 False，但随后又恢复为 True