可定制的 TicTacToe 游戏板 Java
Customizable TicTacToe game board with Java
我需要创建一种方法来检查 tictactoe 游戏是 PLAYING、DRAW、XWIN 还是 OWIN。但是,我很难编写代码来检查 X 或 O 是否获胜,因为游戏板的大小和获胜所需的大小 (sizeWin) 正在根据用户的输入而变化。而且我被迫为游戏板使用一维数组。我根本不知道从这里去哪里。我最近的想法是使用嵌套 for 循环来按行、列或对角线检查是否获胜,但我不确定如何实现它。如果有人对如何解决此问题有任何提示或有任何其他解决方案,我将不胜感激
private void setGameState(int i) {
// Check rows
getLines();
getColumns();
getSizeWin();
for (row = 0; row == lines; row++) {
for (col = 0; col == columns; col++) {
}
}
}
public TicTacToeGame(int lines, int columns, int sizeWin) {
// linesXcolumns game, starts with X, need sizeWin in a line/column/diag to win
this.lines = lines;
this.columns = columns;
CellValue currentCellValue = CellValue.X;
this.sizeWin = sizeWin;
// Creating board according to given size
int size = lines * columns;
this.board = new CellValue[size];
// Setting up board to be empty
for (int i = 0; i < size; i++) {
board[i] = CellValue.EMPTY;
}
}
PS。如果有人调用运算符 TicTacToe(3,4,3),将打印一个 3 行 4 列的游戏板。获胜的 X 或 O 的数量为 3。
CAM$ java TicTacToe 3 4 3
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它比看起来要复杂一点,但在你掌握它之后就很简单了。我制作了一个运行良好的函数:
private static String checkGameState() {
// Looking for errors.
if (rowCount <= 0 || columnCount <= 0) {
return "ERROR: Illegal board size: " + rowCount + "*" + columnCount;
}
if (boradContent.length != rowCount * columnCount) {
return "ERROR: boradContent not compatible with rowSize and columnSize.";
}
if (sizeWin > rowCount && sizeWin > columnCount) {
return "ERROR: Board is too small for this sizeWin: " + sizeWin + ".";
}
String gameState = "PLAYING";
// Checking rows
for (int i = 0; i < rowCount; i++) {
char currentChar = getField(i, 0);
int score = 1;
for (int j = 1; j < columnCount; j++) {
if (currentChar == getField(i, j)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
if (j > columnCount - sizeWin) {
break;
}
score = 1;
currentChar = getField(i, j);
}
}
}
// Checking columns
for (int j = 0; j < columnCount; j++) {
char currentChar = getField(0, j);
int score = 1;
for (int i = 1; i < rowCount; i++) {
if (currentChar == getField(i, j)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
if (j > rowCount - sizeWin) {
break;
}
score = 1;
currentChar = getField(i, j);
}
}
}
// Checking diagonally
// Checking diagonally - from top-left to bottom-right
for (int i = 0; i < rowCount - sizeWin + 1; i++) {
for (int j = 0; j < columnCount - sizeWin + 1; j++) {
char currentChar = getField(i, j);
int score = 1;
for (int k = 1; k < sizeWin; k++) {
if (currentChar == getField(i + k, j + k)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
break;
}
}
}
}
// Checking diagonally - from top-right to bottom-left
for (int i = 0; i < rowCount - sizeWin + 1; i++) {
for (int j = sizeWin -1; j < columnCount; j++) {
char currentChar = getField(i, j);
int score = 1;
for (int k = 1; k < sizeWin; k++) {
if (currentChar == getField(i + k, j - k)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
break;
}
}
}
}
return gameState;
}
值得一提的是 rowCount、columnCount、sizeWin 和 boradContent 变量是 class 级变量,我使用了 getField(int X, int Y)
方法,这不是一件很复杂的事情,但更有用。它只是将给定的字段坐标转换为一维数组中的位置并且 returns 它的内容:
private static char getField(int X, int Y) {
return boradContent[X * columnCount + Y];
}
我需要创建一种方法来检查 tictactoe 游戏是 PLAYING、DRAW、XWIN 还是 OWIN。但是,我很难编写代码来检查 X 或 O 是否获胜,因为游戏板的大小和获胜所需的大小 (sizeWin) 正在根据用户的输入而变化。而且我被迫为游戏板使用一维数组。我根本不知道从这里去哪里。我最近的想法是使用嵌套 for 循环来按行、列或对角线检查是否获胜,但我不确定如何实现它。如果有人对如何解决此问题有任何提示或有任何其他解决方案,我将不胜感激
private void setGameState(int i) {
// Check rows
getLines();
getColumns();
getSizeWin();
for (row = 0; row == lines; row++) {
for (col = 0; col == columns; col++) {
}
}
}
public TicTacToeGame(int lines, int columns, int sizeWin) {
// linesXcolumns game, starts with X, need sizeWin in a line/column/diag to win
this.lines = lines;
this.columns = columns;
CellValue currentCellValue = CellValue.X;
this.sizeWin = sizeWin;
// Creating board according to given size
int size = lines * columns;
this.board = new CellValue[size];
// Setting up board to be empty
for (int i = 0; i < size; i++) {
board[i] = CellValue.EMPTY;
}
}
PS。如果有人调用运算符 TicTacToe(3,4,3),将打印一个 3 行 4 列的游戏板。获胜的 X 或 O 的数量为 3。
CAM$ java TicTacToe 3 4 3
| | |
---------------
| | |
---------------
| | |
它比看起来要复杂一点,但在你掌握它之后就很简单了。我制作了一个运行良好的函数:
private static String checkGameState() {
// Looking for errors.
if (rowCount <= 0 || columnCount <= 0) {
return "ERROR: Illegal board size: " + rowCount + "*" + columnCount;
}
if (boradContent.length != rowCount * columnCount) {
return "ERROR: boradContent not compatible with rowSize and columnSize.";
}
if (sizeWin > rowCount && sizeWin > columnCount) {
return "ERROR: Board is too small for this sizeWin: " + sizeWin + ".";
}
String gameState = "PLAYING";
// Checking rows
for (int i = 0; i < rowCount; i++) {
char currentChar = getField(i, 0);
int score = 1;
for (int j = 1; j < columnCount; j++) {
if (currentChar == getField(i, j)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
if (j > columnCount - sizeWin) {
break;
}
score = 1;
currentChar = getField(i, j);
}
}
}
// Checking columns
for (int j = 0; j < columnCount; j++) {
char currentChar = getField(0, j);
int score = 1;
for (int i = 1; i < rowCount; i++) {
if (currentChar == getField(i, j)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
if (j > rowCount - sizeWin) {
break;
}
score = 1;
currentChar = getField(i, j);
}
}
}
// Checking diagonally
// Checking diagonally - from top-left to bottom-right
for (int i = 0; i < rowCount - sizeWin + 1; i++) {
for (int j = 0; j < columnCount - sizeWin + 1; j++) {
char currentChar = getField(i, j);
int score = 1;
for (int k = 1; k < sizeWin; k++) {
if (currentChar == getField(i + k, j + k)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
break;
}
}
}
}
// Checking diagonally - from top-right to bottom-left
for (int i = 0; i < rowCount - sizeWin + 1; i++) {
for (int j = sizeWin -1; j < columnCount; j++) {
char currentChar = getField(i, j);
int score = 1;
for (int k = 1; k < sizeWin; k++) {
if (currentChar == getField(i + k, j - k)) {
score++;
if (score >= sizeWin) {
if (gameState.equals("PLAYING")) {
gameState = currentChar + "WIN";
} else if (!gameState.equals(currentChar + "WIN")) {
gameState = "DRAW";
return gameState;
}
}
} else {
break;
}
}
}
}
return gameState;
}
值得一提的是 rowCount、columnCount、sizeWin 和 boradContent 变量是 class 级变量,我使用了 getField(int X, int Y)
方法,这不是一件很复杂的事情,但更有用。它只是将给定的字段坐标转换为一维数组中的位置并且 returns 它的内容:
private static char getField(int X, int Y) {
return boradContent[X * columnCount + Y];
}