二维数组中的最小值

Question

我有这个数组：

A = [[30, 80, 50], [44, 60, 41]]

如何获得如下输出：

min = [30, 60, 41]

Answer 1

A = [[30, 80, 50], [44, 60, 41]]
print([min(column) for column in zip(*A)])

输出：

[30, 60, 41]

Answer 2

另一个选项：

A = [[30, 80, 50], [44, 60, 41]]
list(map(min, zip(*A)))

Answer 3

import numpy as np
A = [[30, 80, 50], [44, 60, 41]]
np.min(A, axis=0) # computes minimum in each row

输出：

array([30, 60, 41])

minimum value from an 2dArray