如何在 pygame 中应用碰撞？我已经看到了很多，但没有什么能记住

Question

我迫切需要帮助。几个小时以来，我一直在尝试为我的 pygame 代码实施碰撞，但没有任何效果。我研究了很多方法，但没有一个是我的想法，或者是否有可能实现它们的方法。

代码如下：

import pygame
import  random

pygame.init()

#SCREEN
screeenWidth = 320
screenHeight = 600
screen = pygame.display.set_mode((screeenWidth, screenHeight))
screenBackground = pygame.image.load('assets/background.png')
screen.blit(screenBackground, (0,0))
pygame.display.set_caption("Evading Game")

#CLOCK
clock = pygame.time.Clock()

#PLAYER
playerX = 20 #which is lane 1
playerY = screenHeight * 0.8
playerImage = pygame.image.load('assets/car_img.png')
lane_dictionary = {1:20,2:85,3:160,4:240}
player_current_lane = 1


#OBSTACLE
obstacle_current_lane = random.randint(1,4)
obstacleX = lane_dictionary[obstacle_current_lane]
obstacleY = 0
obstacleImage = pygame.image.load('assets/obstacle_img.png')


running = True
while running:

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        if event.type == pygame.KEYDOWN: 
            if event.key == pygame.K_RIGHT: #Lane 1 = 20, lane 2 = 80, lane 3 = 160, lane 4 = 240
                if not player_current_lane == 4:
                    player_current_lane += 1
                    e = lane_dictionary[player_current_lane]
                    playerX = e
            if event.key == pygame.K_LEFT: #Lane 1 = 20, lane 2 = 80, lane 3 = 160, lane 4 = 240
                if not player_current_lane == 1:
                    player_current_lane -= 1
                    e = lane_dictionary[player_current_lane]
                    playerX = e

    obstacleY += 1 #Obstacle movement

    screen.blit(screenBackground, (0,0)) #Blit background
    screen.blit(playerImage, (playerX, playerY)) #blit player
    screen.blit(obstacleImage, (obstacleX, obstacleY)) #Blit obstacle
    pygame.display.update()


    clock.tick(60) #fps

pygame.quit()
quit()

Answer 1

创建一个 pygame.Rect 对象，大小为 playerImage，玩家位置为（playerX，playerY）。
创建第二个pygame.Rect，大小为obstacleImage，障碍物位置为（obstacleX，obstacleY）。
使用 colliderect 检测两个矩形之间的碰撞。例如：

while running:
    # [...]

    playerRect = playerImage.get_rect(topleft = (playerX, playerY))
    obstacleRect = obstacleImage.get_rect(topleft = (obstacleX, obstacleY))
    if playerRect.colliderect(obstacleRect):
        print("hit")

    # [...]

如何在 pygame 中应用碰撞？我已经看到了很多，但没有什么能记住

How can you apply collision in pygame? I have seen a lot but nothing is sticking to mind

python

pygame

collision