当输入前面是整数输入时，将跳过字符串变量的输入

Question

我正在练习扫描仪的用法和语法，下面是我编写的代码，我在其中尝试从用户那里获取 4 个输入：

    Scanner s= new Scanner(System.in);
    
    int a = s.nextInt();// taking an integer as input, it works fine.
    String b = s.nextLine();//was supposed to take a string input, but not working
    String c=s.nextLine();//takes a string as input from user
    String d=s.nextLine();//takes another string as input from user

    System.out.println("integer entered: "+a);
    System.out.println("first string entered: "+b);
    System.out.println("second string entered: "+c);
    System.out.println("third string entered: "+d);

但用户只能提供 3 个输入，第一个整数和其他两个字符串输入，通过打印这 4 个变量的值，很明显第一个字符串 String b 的输入是 skipped.I 然后尝试重新排列输入的顺序，即

String b = s.nextLine();//takes a string input
int a = s.nextInt();// taking an integer as input
String c=s.nextLine();//was supposed to take a string as input from user
String d=s.nextLine();//takes another string as input from user

在这种情况下，将跳过第二个字符串 String c 的输入。那么，是不是因为整数输入跳过了下一个字符串输入？

Answer 1

这是一个常见问题。

固定码

Scanner s= new Scanner(System.in);
int a = s.nextInt();
s.nextLine();
System.out.print("Enter a string: ");
String b = s.nextLine();
System.out.print("Enter another string: ");
String c=s.nextLine();
System.out.print("Enter one more string: ");
String d=s.nextLine();

System.out.println(a+"\n"+b+d+c);

参考： Scanner is skipping nextLine() after using next() or nextFoo()?

当输入前面是整数输入时，将跳过字符串变量的输入

input for a String variable is skipped when it is preceeded by an integer input

java

string

integer

java.util.scanner