如何使用 python 请求转换 CURL 命令并通过 API 检索结果

Question

我是 python 的新手，在传递我想通过 API 从服务器请求的参数时遇到问题。

我正在使用 Flask，因为我希望它是基于 Web 的。第 1 步：转到 index.html 并传递 teamID teamID = request.form['teamID']。第 2 步：通过 API 验证用户并通过 teamID 查找数据第三步：进入页面report.html并显示结果+将结果保存为CSV文件

import subprocess
import json 
import requests
from flask import Flask, render_template, request

#required parameters
myID = 12345 
teamID = 3456
includeSub = 0 
beginDate = "2020-03-20 00:00:00"
endDate = "2020-03-22 00:00:00" 
Type = 1 
authToken = "1245dgfdfg655432gf"
serverURL = https://myurl.com/env/re/

#optional parameters
Category = 1
fpDate = 1
versionP = "1.0"
-----------------

这是我想转换成 python 请求格式的 CURL 命令：

#Curl command that i need to covert to python requests format
 "curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'"

到目前为止我的代码：

app = Flask(__name__)

@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json', 
        'Content-Type': 'application/json', 
        'accessToken': authToken,
        'userID': myID}
commandBody = {
  "teamID": teamID,
  "includeSub": includeSub,
  "beginDate": beginDate,
  "endDate": endDate,
  "Category": Category,
  "fpDate": fpDate,
  "versionP": versionP
}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)

@app.route('/')
def index():
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug=True)

有人可以帮忙吗？到目前为止，我尝试了上面的代码但收到了 SyntaxError: invalid syntax 或 TabError: inconsistent use of tabs and spaces in indentation

提前致谢！

Answer 1

感谢 TrillWorks，我们现在有了在线 curl 到 python 转换器。
所以对于：

curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'

你有：

import requests

headers = {
    '\Content-Type': 'application/json" -H "accessToken:',
}

response = requests.post('http://&', headers=headers)

可用 HERE。

避免TabError:

app = Flask(__name__)
@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json', 'Content-Type': 'application/json','accessToken': authToken,'userID': myID}
commandBody = {"teamID": teamID,"includeSub": includeSub,"beginDate": beginDate,"endDate": endDate,"Category": Category,"fpDate": fpDate,"versionP": versionP}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)
@app.route('/')
def index():
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug=True)

如何使用 python 请求转换 CURL 命令并通过 API 检索结果

How to convert CURL command with python requests and retrieve results via API

python

curl

flask

python-requests

flask-restful