在 Spritekit 上双重生成（和重叠）敌人

Question

我在无休止的运行游戏中遇到了麻烦，主要是我创建的两种敌人的生成，有时当我们调用函数时会生成两个敌人 "startDifficultyTimer". 基本上，当我调用该函数时，游戏会在同一行中生成 2 个节点，因此玩家被迫失败，我想避免这种情况，但我不知道如何，我几乎尝试了所有方法，我试图从 didmove 中删除 createsequentialenemy但问题仍然存在，我认为（作为新手）问题出在 startDifficultTimer 函数中，因为当值达到极限时问题就消失了我已经在下面发布了代码，对于可能存在的巨大错误，我们深表歉意，但我们是 swift 开发游戏的新手，非常感谢大家！

func createEnemy() {
    let enemy: Enemy
    let duration: CGFloat

    switch Int(arc4random() % 100) {
        case 0...70:
            enemy = Enemy.createEnemy()
            duration =  CGFloat(Float(arc4random()%1)) + durationV
            enemy.physicsBody = SKPhysicsBody(rectangleOf: CGSize(width: 55, height: 37))
            let enemyf = enemy.frame
            let fixedx = frame.width + enemy.frame.width/2.0
            let positions = [ CGPoint(x: fixedx, y: 383), CGPoint(x: fixedx, y: 447), CGPoint(x: fixedx, y: 511)]
            let position = positions[Int(arc4random_uniform(UInt32(positions.count)))]
            enemy.position = position
        case 71...100:
            enemy = Enemy.createEnemyMedium()
            duration =  CGFloat(Float(arc4random()%1)) + durationV
            enemy.physicsBody = SKPhysicsBody(rectangleOf: CGSize(width: 40, height: 70))
            let enemyf = enemy.frame
            let fixedx = frame.width + enemy.frame.width/2.0
            let positions = [ CGPoint(x: fixedx, y: 415), CGPoint(x: fixedx, y: 479)]
            let position = positions[Int(arc4random_uniform(UInt32(positions.count)))]
            enemy.position = position
        default:
            enemy = Enemy.createEnemy()
            //type = .small
            duration =  CGFloat(Float(arc4random()%1)) + durationV
            let enemyf = enemy.frame
            let fixedx = frame.width + enemy.frame.width/2.0
            let positions = [ CGPoint(x: fixedx, y: 383), CGPoint(x: fixedx, y: 447), CGPoint(x: fixedx, y: 511)]
            let position = positions[Int(arc4random_uniform(UInt32(positions.count)))]
            let texture = SKTexture(imageNamed: "dronea1")
            enemy.position = position
    }

    enemy.physicsBody!.isDynamic = false
    enemy.physicsBody!.categoryBitMask = PhysicsCategory.Enemy
    addChild(enemy)

    let moveTo = SKAction.moveTo(x: 0.0, duration: TimeInterval(duration))
    enemy.run(.repeatForever(.sequence([moveTo, .removeFromParent()])))
}

func createSequentialEnemies() {
    // remove previous action if running. This way you can adjust the spawn duration property and call this method again and it will cancel previous action.
    removeAction(forKey: spawnKey)
    let spawnAction = SKAction.run(createEnemy)
    let spawnDelay = SKAction.wait(forDuration: spawnDuration)
    let spawnSequence = SKAction.sequence([spawnAction, spawnDelay])
    run(SKAction.repeatForever(spawnSequence), withKey: spawnKey)later
}

func startDifficultyTimer() {
    let difficultyTimerKey = "DifficultyTimerKey"
    let action1 = SKAction.wait(forDuration: 1)
    let action2 = SKAction.run { [unowned self] in
        guard self.spawnDuration > 0.5 else {  // set a min limit
            self.removeAction(forKey: difficultyTimerKey) // if min duration has been reached than you might as well stop running this timer.
            return
        }
        self.spawnDuration -= 0.5 // reduce by half a second
        self.createSequentialEnemies() // spawn enemies again
    }
    let sequence = SKAction.sequence([action1, action2])
    run(SKAction.repeatForever(sequence), withKey: difficultyTimerKey)
}

Answer 1

我认为问题在于您在计时器更改时说 "stop this action"。但是该语句不知道敌人是刚刚创建还是即将创建。无论它在循环中的哪个位置，您都会停止它并重新开始循环。因此，如果它刚刚创建了一个敌人，而您停止循环并通过更快地生成一个新敌人来重新开始，您将连续获得两个敌人。

解决此问题的方法可能是运行您的顺序相反。暂停然后生成你的敌人。

let spawnSequence = SKAction.sequence([spawnDelay, spawnAction])

你可能会在敌人之间获得稍长的距离，但不会让两个敌人重叠。

否则，您可以在每次生成最后一个敌人时跟踪生成时间，并将其从下一个生成时间中减去，以便在两者之间放置自定义等待操作。

在 Spritekit 上双重生成（和重叠）敌人

double spawning (& overlapping) enemies on Spritekit

xcode

ios

sprite-kit

swift