功能来检查对手之间的平局或平局是否在 python 中的井字游戏中不能正常工作

Question

我正在为一个基本的 "tic tac toe" 游戏编写一个程序，当变量 "won" 在退出游戏结束时返回为 False 时，我想在其中打印 "match draws"我的循环。

虽然一切正常，但最后还是不会打印"match draws"。

还请建议如何缩短或改进它，或者我可以如何改进它。我才刚刚开始。

下面是基本代码：

import numpy
import random
board=numpy.array=["-","-","-"],["-","-","-"],["-","-","-"]
p1s="x"
p2s="o"

def place(symbol):
    print (numpy.matrix(board))
    while(1):
        row=int(input("enter row"))
        col=int(input("enter column"))
        if (row>0 and row <4 and col>0 and col<4 and board[row-1][col-1]=="-"):
            break
        else:
            print("please enter valid input")
    board[row-1][col-1]=symbol
def won(symbol):
    return check_rows(symbol) or check_columns(symbol) or check_diagonals(symbol)
def check_rows(symbol):
    for r in range(3):
        count=0
        for c in range(3):
            if board[r][c]==symbol:
                count+=1
        if (count==3):
            print(numpy.matrix(board))
            print(symbol,"won")
            return True
    return False
def check_columns(symbol):
    for c in range(3):
        count=0
        for r in range(3):
            if board[r][c]==symbol:
                count+=1
        if (count==3):
            print(numpy.matrix(board))
            print(symbol,"won")
            return True
    return False
def check_diagonals(symbol):
    if (board[0][0] == board[1][1] and board[1][1]==board[2][2] and board[1][1]==symbol):
        print(numpy.matrix(board))
        print(symbol,"won")
        return True
    if (board[0][2] == board[1][1] and board[1][1]==board[2][0] and board[1][1]==symbol):
        print(numpy.matrix(board))
        print(symbol,"won")
        return True
    return False


def play():
    turn=start+1
    count=1
    for count in range(8):
        if turn%2==0:
                print("count is",count)
                count+=1
                turn+=1
                print("X turn")
                place(p1s)
                if won(p1s):
                    break
        else:
            print("count is",count)
            count+=1
            turn+=1
            print("O turn")
            place(p2s)
            if won(p2s):
                break
    if (won==False):
        print("match draws")



start=random.randint(1,100)
print(start)
if (start%2==0):
    print("X turn")
    place(p1s)
    play()
else:
    print("O turn")
    place(p2s)
    play()

Answer 1

won 是一个函数对象，因此您不能简单地将它与布尔值进行比较并期望比较结果为真。

如果循环没有 break 找到玩家获胜，您可以改为使用 for-else 构造将游戏视为平局。

变化：

if (won==False):
    print("match draws")

至：

else:
    print("match draws")

功能来检查对手之间的平局或平局是否在 python 中的井字游戏中不能正常工作

function to check if match draws or ties between the opponents not working properly in tic tac toe in python

python

tic-tac-toe