使用 JAXB 将 CSV 文件转换为 JAVA 中的层次结构 XML

Question

我需要使用 CSV 文件创建分层 XML。

id,firstname,Lastname
1,yong,mook kim
2, Alez, Aunritod
,...

我尝试使用 JAXB 并手动创建类

public class WriteXMLFile {

    public static void main(String argv[]) {

      try {

        DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder docBuilder = docFactory.newDocumentBuilder();

        // root elements
        Document doc = docBuilder.newDocument();
        Element rootElement = doc.createElement("company");
        doc.appendChild(rootElement);

        // staff elements
        Element staff = doc.createElement("Staff");
        rootElement.appendChild(staff);

        // set attribute to staff element
        Attr attr = doc.createAttribute("id");
        attr.setValue("1");
        staff.setAttributeNode(attr);

        Element firstname = doc.createElement("firstname");
        firstname.appendChild(doc.createTextNode("yong"));
        staff.appendChild(firstname);

        // lastname elements
        Element lastname = doc.createElement("lastname");
        lastname.appendChild(doc.createTextNode("mook kim"));
        staff.appendChild(lastname);

但我的问题是我想从我的 csv 文件中读取每个节点的值，而不是在代码中手动读取

        Element firstname = doc.createElement("firstname");
        firstname.appendChild(doc.createTextNode("yong"));
        staff.appendChild(firstname);

任何人都可以帮助我如何从我的 sample.csv 文件而不是手动读取它？

Answer 1

尝试以下解决方案，

首先读取csv文件并从各个行中收集对象（人）。然后将对象列表编组到 xml 文件

People.java（xml 文件的根元素）

@XmlRootElement(name="people")
@XmlAccessorType (XmlAccessType.FIELD)
public class People {

    @XmlElement(name="person")
    private List<Person> listPerson;

    public List<Person> getListPerson() {
        return listPerson;
    }
    public void setListPerson(List<Person> listPerson) {
        this.listPerson = listPerson;
    }
}

Person.java（父（人）元素的子元素）

@XmlRootElement(name="person")
@XmlAccessorType (XmlAccessType.FIELD)
public class Person {

    private String id;
    private String firstName;
    private String lastName;

    public String getId() {
        return id;
    }
    public void setId(String id) {
        this.id = id;
    }
    public String getFirstName() {
        return firstName;
    }
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }
    public String getLastName() {
        return lastName;
    }
    public void setLastName(String lastName) {
        this.lastName = lastName;
    }
}

使用 java

编组

public class Marshaller {

    public static void main(String[] args) {

        BufferedReader br;
        String line;
        People people = new People();
        ArrayList<Person> list = new ArrayList();

        //read the csv file and collect the person objects
        try {
            br = new BufferedReader(new FileReader("inputCSV.csv"));
            while ((line = br.readLine()) != null) {    //get every single line individually in csv file
                String[] value = line.split(",");   //collect the comma separated values into array
                Person person = new Person();
                person.setId(value[0]); //first element of an array is id
                person.setFirstName(value[1]);  //second element of an array is firstName
                person.setLastName(value[2]);   //third element of an array is lastName
                list.add(person);   //add person object into the list
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
        people.setListPerson(list); //set person object list to people
        people.getListPerson().remove(0);   //remove the first person object of list. because it holds the column's names

        //marshaling with java
        try {

            JAXBContext jaxbContext = JAXBContext.newInstance(People.class);
            javax.xml.bind.Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
            jaxbMarshaller.setProperty(javax.xml.bind.Marshaller.JAXB_FORMATTED_OUTPUT, true);
            jaxbMarshaller.marshal(people, new File("output.xml"));
            jaxbMarshaller.marshal(people, System.out);

        } catch (JAXBException e) {
            e.printStackTrace();
        }

    }
}

inputCSV.csv

id,firstname,Lastname
1,yong,mook kim
2, Alez, Aunritod

output.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<people>
    <person>
        <id>1</id>
        <firstName>yong</firstName>
        <lastName>mook kim</lastName>
    </person>
    <person>
        <id>2</id>
        <firstName> Alez</firstName>
        <lastName> Aunritod</lastName>
    </person>
</people>

使用 JAXB 将 CSV 文件转换为 JAVA 中的层次结构 XML

Converting CSV File to Hierarchy XML in JAVA with JAXB

java

xml

csv

jaxb