如何通过长按从网页视图中获取 URL?
How to get URL from web view in long click?
我有一个网络视图,当用户长按链接时,我想获得 URL。我知道我可以做到:
// Register the context menu for web view
registerForContextMenu(webView);
并且:
@Override
public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
final WebView.HitTestResult result = webView.getHitTestResult();
Log.i("url is ===" , "result.getExtra()")
}
但是这样一来,在一些搜索引擎如Google中,就不是return一个URL了。这是我长按 google 搜索结果时的日志:
data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAYAAAAf8/9hAAAA+klEQVR4AWMgBnwr4pRloAR8KuA89KmAK4V8A/LZ1YGGvPiQy65MtCaQjR8LuDxh/M8FXNlAQ078D2VgJs6APE6rjwWcj4CaOkGaIIZybPucz1FHvCuyeYVBmkBhAArIL6XcEiCvfCzkNMOpCeRPoPMXgFyACAPOcnAYFLK7fSrkDAR6rQmnAe/KBfmBNhQCDbkGtP0yyO8gsU+FHLYgL4EClGgvgDR9zudcCrT9PchVX4q49YmKc5AmkLNBsQDyOygsQK4iygCQoo8FHLGg0AcFIDQm3gPpvXg1zlu88j++2ACFPB51CAmgbf9xYcIGEAAEDSAWM1ATAAC4CbdSzzGZLwAAAABJRU5ErkJggg==
我从 GitHub 下载了一个 web browser 开源软件。在这个项目中,程序员这样做了,这是可行的:
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
Handler mHandler = new Handler() {
@Override
public void handleMessage(Message msg) {
// Get link-URL.
String url = (String) msg.getData().get("url");
Log.i("get url" , url);
}
};
所以我在我的应用程序中写了这段代码,但是 handleMessage 不是 运行。我需要做任何其他事情才能使用 handleMessage 方法吗?
您知道另一种在 google 搜索结果中获得 URL 的方法吗?
终于,经过几天的努力,我找到了解决办法。请试试这个方法:
@Override
public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
String url = null, imageUrl = null;
WebView.HitTestResult result = ((WebView) v).getHitTestResult();
switch (result.getType()) {
case WebView.HitTestResult.SRC_ANCHOR_TYPE:
url = result.getExtra();
break;
case WebView.HitTestResult.IMAGE_TYPE:
imageUrl = result.getExtra();
break;
case WebView.HitTestResult.SRC_IMAGE_ANCHOR_TYPE:
case WebView.HitTestResult.EMAIL_TYPE:
case WebView.HitTestResult.UNKNOWN_TYPE:
Handler handler = new Handler();
Message message = handler.obtainMessage();
((WebView) v).requestFocusNodeHref(message);
url = message.getData().getString("url");
if ("".equals(url)) {
url = null;
}
imageUrl = message.getData().getString("src");
if ("".equals(imageUrl)) {
imageUrl = null;
}
break;
}
showLongPressMenu(url, imageUrl);
}
我有一个网络视图,当用户长按链接时,我想获得 URL。我知道我可以做到:
// Register the context menu for web view
registerForContextMenu(webView);
并且:
@Override
public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
final WebView.HitTestResult result = webView.getHitTestResult();
Log.i("url is ===" , "result.getExtra()")
}
但是这样一来,在一些搜索引擎如Google中,就不是return一个URL了。这是我长按 google 搜索结果时的日志:
data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAYAAAAf8/9hAAAA+klEQVR4AWMgBnwr4pRloAR8KuA89KmAK4V8A/LZ1YGGvPiQy65MtCaQjR8LuDxh/M8FXNlAQ078D2VgJs6APE6rjwWcj4CaOkGaIIZybPucz1FHvCuyeYVBmkBhAArIL6XcEiCvfCzkNMOpCeRPoPMXgFyACAPOcnAYFLK7fSrkDAR6rQmnAe/KBfmBNhQCDbkGtP0yyO8gsU+FHLYgL4EClGgvgDR9zudcCrT9PchVX4q49YmKc5AmkLNBsQDyOygsQK4iygCQoo8FHLGg0AcFIDQm3gPpvXg1zlu88j++2ACFPB51CAmgbf9xYcIGEAAEDSAWM1ATAAC4CbdSzzGZLwAAAABJRU5ErkJggg==
我从 GitHub 下载了一个 web browser 开源软件。在这个项目中,程序员这样做了,这是可行的:
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
Handler mHandler = new Handler() {
@Override
public void handleMessage(Message msg) {
// Get link-URL.
String url = (String) msg.getData().get("url");
Log.i("get url" , url);
}
};
所以我在我的应用程序中写了这段代码,但是 handleMessage 不是 运行。我需要做任何其他事情才能使用 handleMessage 方法吗?
您知道另一种在 google 搜索结果中获得 URL 的方法吗?
终于,经过几天的努力,我找到了解决办法。请试试这个方法:
@Override
public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
String url = null, imageUrl = null;
WebView.HitTestResult result = ((WebView) v).getHitTestResult();
switch (result.getType()) {
case WebView.HitTestResult.SRC_ANCHOR_TYPE:
url = result.getExtra();
break;
case WebView.HitTestResult.IMAGE_TYPE:
imageUrl = result.getExtra();
break;
case WebView.HitTestResult.SRC_IMAGE_ANCHOR_TYPE:
case WebView.HitTestResult.EMAIL_TYPE:
case WebView.HitTestResult.UNKNOWN_TYPE:
Handler handler = new Handler();
Message message = handler.obtainMessage();
((WebView) v).requestFocusNodeHref(message);
url = message.getData().getString("url");
if ("".equals(url)) {
url = null;
}
imageUrl = message.getData().getString("src");
if ("".equals(imageUrl)) {
imageUrl = null;
}
break;
}
showLongPressMenu(url, imageUrl);
}