剥离 lxml 中的单个元素

Question

我需要删除一个 XML 元素，同时保留其数据。 lxml 函数 strip_tags 确实删除了元素，但它是递归工作的，我想删除单个元素。

我尝试使用 answer on this post，但 remove 删除了整个元素。

xml="""
<groceries>
  One <fruit state="rotten">apple</fruit> a day keeps the doctor away.
  This <fruit state="fresh">pear</fruit> is fresh.
</groceries>
"""

tree=ET.fromstring(xml)

for bad in tree.xpath("//fruit[@state='rotten']"):
    bad.getparent().remove(bad)

print (ET.tostring(tree, pretty_print=True))

我想得到

<groceries>
    One apple a day keeps the doctor away.
    This <fruit state="fresh">pear</fruit> is fresh.
</groceries>\n'

我明白了

<groceries>
    This <fruit state="fresh">pear</fruit> is fresh.
</groceries>\n'

我尝试使用 strip_tags:

for bad in tree.xpath("//fruit[@state='rotten']"):
    ET.strip_tags(bad.getparent(), bad.tag)

<groceries>
    One apple a day keeps the doctor away.
    This pear is fresh.
</groceries>

但这会删除所有内容，我只想删除带有 state='rotten' 的元素。

Answer 1

也许其他人有更好的主意，但这是一个可能的解决方法：

bad = tree.xpath(".//fruit[@state='rotten']")[0] #for simplicity, I didn't bother with a for loop in this case
txt = bad.text+bad.tail # collect the text content of bad; strangely enough it's not just 'apple'
bad.getparent().text += txt # add the collected text to the parent's existing text
tree.remove(bad) # this gets rid only of this specific 'bad'
print(etree.tostring(tree).decode())

输出：

<groceries>
  One apple a day keeps the doctor away.
  This <fruit state="fresh">pear</fruit> is fresh.
</groceries>

剥离 lxml 中的单个元素

Strip a single element in lxml

python

xml

lxml