如何在 Django 中对 ListView 的 get_context_data() 进行单元测试?
How can I unittest get_context_data() of a ListView in Django?
我尝试在 Django 3.0.5 中为 ListView 编写单元测试。我需要检查上下文中包含的数据。此视图的应用程序 运行ning,因此不太可能在实施中出错。但是我在设置测试时错过了什么?
这里是我的部分来源:
urls.py:
app_name = 'gene'
urlpatterns = [
path('persons/', views.PersonList.as_view(), name='person-list'),
...
]
views.py
from django.views.generic.list import ListView
from gene.models import Person
class PersonList(ListView):
model = Person
def get_context_data(self, **kwargs):
context = super(PersonList, self).get_context_data(**kwargs) # this is line 11
...
return context
tests.py:
from django.test import TestCase, RequestFactory
from django.urls import reverse
from gene.models import Person
from gene.views import PersonList
class PersonListTest(TestCase):
def setUp(self):
person1 = Person.objects.create(name="Person 1")
person2 = Person.objects.create(name="Person 2")
def test_context(self):
request = RequestFactory().get(reverse('gene:person-list'))
view = PersonList()
view.setup(request)
context = view.get_context_data() # this is line 20, Error here
self.assertIn('environment', context)
我遵循了官方文档中的指南。
但是当我 运行 这个测试时,我在控制台上得到以下信息:
Error
Traceback (most recent call last):
File "/home/macbarfuss/PycharmProjects/Genealogy/gene/tests.py", line 20, in test_context
context = view.get_context_data()
File "/home/macbarfuss/PycharmProjects/Genealogy/gene/views.py", line 11, in get_context_data
context = super(PersonList, self).get_context_data(**kwargs)
File "/home/macbarfuss/PycharmProjects/Genealogy/venv/lib/python3.8/site-packages/django/views/generic/list.py", line 115, in get_context_data
queryset = object_list if object_list is not None else self.object_list
AttributeError: 'PersonList' object has no attribute 'object_list'
有什么想法吗?
Django 有一个 Client
[Django-doc] 允许您检查 context
。请注意,通常上下文 不会 在 HTTP 响应中导出,但在此处进行了修补以允许进行测试:
import unittest
from django.test import <b>Client</b>
class SimpleTest(unittest.TestCase):
def setUp(self):
self.client = Client()
person1 = Person.objects.create(name="Person 1")
person2 = Person.objects.create(name="Person 2")
def test_details(self):
response = self.client.get(reverse('gene:person-list'))
self.assertIn('environment', <b>response.context</b>)
所以 response
有一个 .context
attribute [Django-doc]。
我建议使用 Client
,因为基于 class 的视图非常复杂,流程可以 "decyphered",但它需要一些技巧,通过使用简单的 .dispatch()
,等等。你只检索到 HttpResponse
而没有 .context
,所以最好使用 Django 为这个任务提供的工具。
我尝试在 Django 3.0.5 中为 ListView 编写单元测试。我需要检查上下文中包含的数据。此视图的应用程序 运行ning,因此不太可能在实施中出错。但是我在设置测试时错过了什么?
这里是我的部分来源:
urls.py:
app_name = 'gene'
urlpatterns = [
path('persons/', views.PersonList.as_view(), name='person-list'),
...
]
views.py
from django.views.generic.list import ListView
from gene.models import Person
class PersonList(ListView):
model = Person
def get_context_data(self, **kwargs):
context = super(PersonList, self).get_context_data(**kwargs) # this is line 11
...
return context
tests.py:
from django.test import TestCase, RequestFactory
from django.urls import reverse
from gene.models import Person
from gene.views import PersonList
class PersonListTest(TestCase):
def setUp(self):
person1 = Person.objects.create(name="Person 1")
person2 = Person.objects.create(name="Person 2")
def test_context(self):
request = RequestFactory().get(reverse('gene:person-list'))
view = PersonList()
view.setup(request)
context = view.get_context_data() # this is line 20, Error here
self.assertIn('environment', context)
我遵循了官方文档中的指南。
但是当我 运行 这个测试时,我在控制台上得到以下信息:
Error
Traceback (most recent call last):
File "/home/macbarfuss/PycharmProjects/Genealogy/gene/tests.py", line 20, in test_context
context = view.get_context_data()
File "/home/macbarfuss/PycharmProjects/Genealogy/gene/views.py", line 11, in get_context_data
context = super(PersonList, self).get_context_data(**kwargs)
File "/home/macbarfuss/PycharmProjects/Genealogy/venv/lib/python3.8/site-packages/django/views/generic/list.py", line 115, in get_context_data
queryset = object_list if object_list is not None else self.object_list
AttributeError: 'PersonList' object has no attribute 'object_list'
有什么想法吗?
Django 有一个 Client
[Django-doc] 允许您检查 context
。请注意,通常上下文 不会 在 HTTP 响应中导出,但在此处进行了修补以允许进行测试:
import unittest
from django.test import <b>Client</b>
class SimpleTest(unittest.TestCase):
def setUp(self):
self.client = Client()
person1 = Person.objects.create(name="Person 1")
person2 = Person.objects.create(name="Person 2")
def test_details(self):
response = self.client.get(reverse('gene:person-list'))
self.assertIn('environment', <b>response.context</b>)
所以 response
有一个 .context
attribute [Django-doc]。
我建议使用 Client
,因为基于 class 的视图非常复杂,流程可以 "decyphered",但它需要一些技巧,通过使用简单的 .dispatch()
,等等。你只检索到 HttpResponse
而没有 .context
,所以最好使用 Django 为这个任务提供的工具。