如何从列表中插入的元组中删除括号？

Question

有人可以帮我从元组列表中删除多余的括号吗？

latest_Value = {"17:00:00": 100.00}

Dict1 = {"current value": 100, "stock_purchased": "false", "Historic value": [('16:00:00', 55.50), ("15:00:00", 45.50), ("14:00:00", 75.50),("13:00:00", 65.50), ("12:00:00", 55.50)]}

# converting the latest_value into a tuple
List_it = [(k, v) for k, v in latest_Value.items()]

# insert the tuple into the tuple list
Dict1['Historic value'].insert(0, List_it)

data2 = Dict1["Historic value"]
print(data2)

#output 

[[('17:00:00', 100.0)], ('16:00:00', 55.5), ('15:00:00', 45.5), ('14:00:00', 75.5), ('13:00:00', 65.5), ('12:00:00', 55.5)]

修改列表时，它会添加一个嵌套列表，而不仅仅是元组。你如何避免这种情况？

亲切的问候，

安德鲁

Answer 1

# converting the latest_value into a tuple
List_it = [(k, v) for k, v in latest_Value.items()]

也就是说，其实是错误的。这会将整个字典转换为元组，而不仅仅是最后一个键值对，因此 Dict1['Historic value'].insert(0, List_it) 将整个元组列表添加到 Dict1['Historic value'].

latest_Value 包含单个键值对的事实不会改变 List_it 将是元组列表的事实。

如果你改为Dict1['Historic value'].insert(0, List_it[0])那么你会得到你想要的输出。

如何从列表中插入的元组中删除括号？

how to remove brackets from an inserted tuple in a list?

python

tuples

brackets

list