通过比较列表项删除 XML 个节点

Question

我一直致力于从 XML 中删除几个 XML 节点 string.My 要求是删除与列表项匹配的 XML 节点。我试图获取 childNodes 并检查 childNode 的名称是否在属性列表中。我已经生成了 MovieDetails class 中存在的属性列表。

public class MovieDetails 
    {
        public string MovieName { get; set; }
        public string MovieId { get; set; }
        public string MovieGenre { get; set; }
    }

MyXml:

<MovieContent>
  <MovieDetails>
      <MovieName>Movie_Name_1</MovieName>
      <MovieId>MovieId_1</MovieId>
      <MovieGenre>MovieGenre_3</MovieGenre>
      <AdditionalInformation>HAHAHHAHA</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
      <MovieName>Movie_Name_2</MovieName>
      <MovieId>MovieId_2</MovieId>
      <MovieGenre>MovieGenre_3</MovieGenre> 
      <AdditionalInformation>FOOOO</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
      <MovieName>Movie_Name_3</MovieName>
      <MovieId>MovieId_3</MovieId>
      <MovieGenre>MovieGenre_3</MovieGenre> 
      <AdditionalInformation></AdditionalInformation>
  </MovieDetails>
</MovieContent>

我尝试使用 for 循环但无法从下面的代码中获得我想要的 result.But 我每次都可以在 1 个节点上删除。

 var movieDetailsNode = xmlContent.DocumentElement.ChildNodes;
 var properties = typeof(MovieDetails).GetProperties().Select(x => x.Name).ToList();
    foreach (XmlNode node in movieDetailsNode )
    {
       var childNodeList = node.ChildNodes;
       for (int i = 0; i < childNodeList.Count; i++)
       {
           var childNodeName = childNodeList[0].Name;
           if (properties.Contains(childNodeName))
           {
               childNodeList[i].ParentNode.RemoveChild(childNodeList[i]);
           }
        }
     }

任何人都可以帮助实现以下结果 xml

结果XML：

<MovieContent>
  <MovieDetails>
      <AdditionalInformation>HAHAHHAHA</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
      <AdditionalInformation>FOOOO</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
      <AdditionalInformation></AdditionalInformation>
  </MovieDetails>
</MovieContent>

Answer 1

这会起作用

            var movieDetailsNode = xmlContent.DocumentElement.ChildNodes;
            var properties = typeof(MovieDetails).GetProperties().Select(x => x.Name).ToList();
            foreach (XmlNode node in movieDetailsNode)
            {
                var childNodeList = node.ChildNodes;
                for (int i = 0; i < childNodeList.Count; i++)
                {
                   // replace '0' with 'i'
                    var childNodeName = childNodeList[i].Name;
                    if (properties.Contains(childNodeName))
                    {                       
                        childNodeList[i].ParentNode.RemoveChild(childNodeList[i]);
                        // add decrement of 'i' here
                        i--;
                    }
                }
            }

Answer 2

一种更简单的方法是使用 LINQ to XML from the System.Xml.Linq 命名空间从您的属性集合中删除节点。在这里使用 HashSet<string> 是有意义的，因为名称应该是唯一的并且查找时间是恒定的而不是线性的。

var properties = typeof(MovieDetails)
    .GetProperties()
    .Select(x => x.Name)
    .ToHashSet();

// Or just var properties = new HashSet<string> { "MovieName", "MovieId", "MovieGenre" };

var doc = XElement.Load(@"C:\input.xml");

doc.Descendants("MovieDetails")
   .Elements()
   .Where(e => properties.Contains(e.Name.LocalName))
   .Remove();

doc.Save(@"C:\output.xml");

说明

使用Descendants()获取MovieTitle个节点。
获取所有带Elements()的子元素。
用Enumerable.Where and HashSet<T>.Contains(T)过滤掉散列集中不存在的元素。
使用 Remove() 从父节点中删除节点。

output.xml

<MovieContent>
  <MovieDetails>
    <AdditionalInformation>HAHAHHAHA</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
    <AdditionalInformation>FOOOO</AdditionalInformation>
  </MovieDetails>
  <MovieDetails>
    <AdditionalInformation></AdditionalInformation>
  </MovieDetails>
</MovieContent>

通过比较列表项删除 XML 个节点

Removing XML Nodes by Comparing the List items

.net

c#

xml

c#-4.0

asp.net-core