如何从通知中获取 link 并通过 firebase 在 mainactivity webview 中打开？

Question

我在做什么： 通过这些代码，我收到来自 Firebase 的通知和打开 mainactivity webview 默认值的 onclick 通知 url。

我想做什么：我想在我将通过 Firebase 发送的 mainactivity webview 中打开 url。

我不知道如何实现这个（从 Firebase 通知接收 url 并在 mainactivity webview 中打开）

notification.java

public class FirebaseMessageReciver extends FirebaseMessagingService {
        @Override
        public void onMessageReceived(RemoteMessage remoteMessage) {
            //handle when receive notification via data event
            if (remoteMessage.getData().size()>0){
                showNotification(remoteMessage.getData().get("title"),remoteMessage.getData().get("message"),remoteMessage.getData().get("link"));
            }
            //handle when receive notification
            if(remoteMessage.getNotification()!=null){
                showNotification(remoteMessage.getNotification().getTitle(),remoteMessage.getNotification().getBody());
            }
        }

        private RemoteViews getCustomDesign(String title,String message) {
            RemoteViews remoteViews = new RemoteViews(getApplicationContext().getPackageName(), R.layout.notification);
            remoteViews.setTextViewText(R.id.title,title);
            remoteViews.setTextViewText(R.id.message,message);
            remoteViews.setImageViewResource(R.id.icon,R.mipmap.ic_launcher_round);
            return remoteViews;

        }

        public void showNotification(String title,String message,String link){
            Intent intent = new Intent(this, MainActivity.class);
            String channel_id = "web_app_channel";
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);
            Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
            NotificationCompat.Builder builder = new NotificationCompat.Builder(getApplicationContext(),channel_id)
                    .setSmallIcon(R.mipmap.ic_launcher_round)
                    .setSound(uri)
                    .setAutoCancel(true)
                    .setVibrate(new long[] {1000, 1000, 1000, 1000, 1000})
                    .setOnlyAlertOnce(true)
                    .setContentIntent(pendingIntent);

            if(Build.VERSION.SDK_INT>=Build.VERSION_CODES.JELLY_BEAN){
                builder=builder.setContent(getCustomDesign(title, message));
            }
            else{
                builder= builder.setContentTitle(title)
                        .setContentText(message)
                        .setSmallIcon(R.mipmap.ic_launcher_round);
            }

            NotificationManager notificationManager= (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
            if(Build.VERSION.SDK_INT>=Build.VERSION_CODES.O){
                NotificationChannel notificationChannel = new NotificationChannel(channel_id,"web_app",NotificationManager.IMPORTANCE_HIGH);
                notificationChannel.setSound(uri, null);
                notificationManager.createNotificationChannel(notificationChannel);
            }

            notificationManager.notify(0,builder.build());

        }
    }

mainactivity.java

public class MainActivity extends AppCompatActivity {


    String webAdress = "https://google.com";
    WebView webView;


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Log.d("Token", ""+ FirebaseInstanceId.getInstance().getToken());
        FirebaseMessaging.getInstance().subscribeToTopic("allDevices");
        webView = (WebView) findViewById(R.id.webView);
        webView.setWebViewClient(new HelpClient());
        webView.getSettings().setJavaScriptEnabled(true); //enable javascript
        webView.loadUrl(webAdress);
}

    private class HelpClient extends WebViewClient {
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return true;
        }

    }
}

Answer 1

你可以使用intent.putExtra

像这样在您的代码中添加它。

Intent intent = new Intent(this, MainActivity.class);
String channel_id = "web_app_channel";
intent.putExtra("link", link);  // add this line for send url
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);

并在 MainActivity 中添加 getIntent

Log.d("Token", ""+ FirebaseInstanceId.getInstance().getToken());
FirebaseMessaging.getInstance().subscribeToTopic("allDevices");

String urlFromFirebase = getIntent().getStringExtra("link"); //get link from firebase

// for exception
if (urlFromFirebase.equals("")) {
   urlFromFirebase = "https://google.com";
}

webView = (WebView) findViewById(R.id.webView);
webView.setWebViewClient(new HelpClient());
webView.getSettings().setJavaScriptEnabled(true); //enable javascript
webView.loadUrl(urlFromFirebase ); //load

然后您可以从 firebase 加载 url。

[编辑] 我创立了

showNotification(remoteMessage.getData().get("title"),remoteMessage.getData().get("message"),remoteMessage.getData().get("link"));

此代码在您编辑之前，所以如果您想编辑。试试这个代码。

@Override
        public void onMessageReceived(RemoteMessage remoteMessage) {
            //handle when receive notification via data event
            if (remoteMessage.getData().size()>0){
                showNotification(remoteMessage.getData().get("body"));
            }
            //handle when receive notification
            if(remoteMessage.getNotification()!=null){
                showNotification(remoteMessage.getData().get("body"));
            }
        }


    private void sendNotification(String messageBody) {
        try {
        JSONObject jsonBody = new JSONObject(messageBody);

        Intent intent = new Intent(this, MainActivity.class);
        String channel_id = "web_app_channel";

       // you can edit this part as you want or follow data.
        String title = jsonBody.getString("title");
        String message = jsonBody.getString("message");
        String link = jsonBody.getJSONObject("data").getString("link");

        intent.putExtra("link", link);
        intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);
        Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        NotificationCompat.Builder builder = new NotificationCompat.Builder(getApplicationContext(),channel_id)
                .setSmallIcon(R.mipmap.ic_launcher_round)
                .setSound(uri)
                .setAutoCancel(true)
                .setVibrate(new long[] {1000, 1000, 1000, 1000, 1000})
                .setOnlyAlertOnce(true)
                .setContentIntent(pendingIntent);

        if(Build.VERSION.SDK_INT>=Build.VERSION_CODES.JELLY_BEAN){
            builder=builder.setContent(getCustomDesign(title, message));
        }
        else{
            builder= builder.setContentTitle(title)
                    .setContentText(message)
                    .setSmallIcon(R.mipmap.ic_launcher_round);
        }

        NotificationManager notificationManager= (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        if(Build.VERSION.SDK_INT>=Build.VERSION_CODES.O){
            NotificationChannel notificationChannel = new NotificationChannel(channel_id,"web_app",NotificationManager.IMPORTANCE_HIGH);
            notificationChannel.setSound(uri, null);
            notificationManager.createNotificationChannel(notificationChannel);
        }

            notificationManager.notify(0,builder.build());
        } catch (JSONException e) {
            e.printStackTrace();
        }
        }

在我的例子中，我创建了 JSONObject，并获取了 link 表单数据。试试这个。

如何从通知中获取 link 并通过 firebase 在 mainactivity webview 中打开？

how to get link from notification and open in mainactivity webview by firebase?

android

webview

push-notification

firebase