查询构建器 GROUP BY，HAVING，COUNT in Laravel

Question

如何在查询生成器中表达此代码。我正在使用 Laravel 6.

SELECT * FROM feedback GROUP BY noTicket having count(`status`) < 2

我的代码：

$feedback = DB::table('feedback')
            ->groupBy('noTicket')
            ->having('count(status)', '<', 2)
            ->get();

错误代码：

SQLSTATE[42000]: Syntax error or access violation: 1055 'sifora.feedback.idFeedback' isn't in GROUP BY 
(SQL: select * from `feedback` group by `noTicket` having `count(status)` < 2)

我的代码有什么问题？ sql 代码与查询生成器之间似乎匹配。

谢谢

Answer 1

这是查询的工作版本

select noTicket
from feedback
group by noTicket
having count(status) < 2;

这是查询生成器；

return DB::table('feedback')
    ->groupBy('noTicket')
    ->having(DB::raw('count(status)'), '<', 2)
    ->pluck('noTicket'); // you may replace this with get()/select()

Answer 2

这里是完整的代码。非常感谢 Ersoy

        $getArray = DB::table('feedback')
            ->groupBy('noTicket')
            ->having(DB::raw('count(status)'), '<', 2)
            ->pluck('noTicket');
        $feedback = DB::table('feedback')
            ->whereIn('noTicket', $getArray)->get();

Answer 3

$feedback  = DB::table('feedback')
    ->selectRaw('feedback.*, count(status) as count_status')
    ->groupBy('noTicket')
    ->havingRaw('count(status) > ?', [2])
    ->get();

还有严格模式，你可以在config/database.php

中禁用它

'connections' => [
    'mysql' => [
        'strict' => false
    ]
]

但我不建议你这样做。在此处查看此 https://dev.mysql.com/doc/refman/5.7/en/group-by-handling.html 以获得更多信息，了解分组方式的工作原理。

查询构建器 GROUP BY，HAVING，COUNT in Laravel

Query builder GROUP BY, HAVING, COUNT in Laravel

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