必须调用对非静态成员函数的引用

Question

以下代码旨在根据第一列对二维向量进行排序，但 returns 出现错误：

Line 8: Char 43: fatal error: reference to non-static member function must be called sort(people.begin(),people.end(), sortfunc); ^~~~~~~~ 1 error generated.

class Solution {
public:

bool sortfunc(const vector<int>& v1, const vector<int>& v2){
    return v1[0]<v2[0];
  }
vector<vector<int>> reconstructQueue(vector<vector<int>>& people) {
    sort(people.begin(),people.end(), sortfunc);
    return people;
  }
};

Answer 1

正如@SevastianHoffmann 所建议的，lambda 函数可以完成这项工作。

    class Solution {
    public:
}
    vector<vector<int>> reconstructQueue(vector<vector<int>>& people) {
        sort(people.begin(),people.end(), [](const vector<int>& v1, const vector<int>& v2){
        return v1[0]<v2[0];
      });
    return people;
  }
};

必须调用对非静态成员函数的引用

Rference to non-static member function must be called

c++

function-pointers