无法在 Node.js 中等待 sqlite3.Database.get() 函数完成

Question

我在使用 node-sqlite3 的 node.js 中遇到一些基本的 async/await 问题。
我的 objective 是 select 来自 SQLite 数据库的某个值，检查它是否符合某些条件并在满足条件时采取一些措施。这是代码：

const sqlite3 = require('sqlite3').verbose();
main();

async function main() {
    let ordersDb = await createDbConnection('./ProcessedOrders.db');
    var orderProcessed = await orderAlreadyProcessed(ordersDb, "555");
    console.log("orderProcessed = " + orderProcessed);
    if (!orderProcessed) {
        console.log("So condition is met!");
    }
}


async function orderAlreadyProcessed(ordersDb, orderNumberStr) {
    console.log('starting orderAlreadyProcessed function'); //DEBUG
    var result;
    var query = 'select count(SoldOrderNumber) as "recsCount" from ProcessedSoldOrders where SoldOrderNumber = ?;';
    await ordersDb.get(query
    ,[orderNumberStr]
    ,(err, row) => {
        console.log('Row with count = ' + row); //DEBUG
        console.log('row.recsCount = ' + row.recsCount); //DEBUG
        result = typeof row !== 'undefined' && row.recsCount > 0;
    });
    console.log('Returning ' + result); //DEBUG
    return result;
}

async function createDbConnection(dbFileName) {
    let db = new sqlite3.Database(dbFileName, (err) => {
        if (err) {
            console.log(err.message);
        }
    });
    return db;
}

但我得到的是进一步执行的代码，根本没有等待 Database.get() 方法！结果，这是我在控制台中看到的打印内容：

starting orderAlreadyProcessed function
Returning undefined
orderProcessed = undefined
So IF condition met!
Row with count = [object Object]
row.recsCount = 1

正如我们所见，我们从 orderAlreadyProcessed 中 return 过早 return 值 = 'undefined'。所以满足条件，采取行动，然后才 Database.get() returns。但如果适当等待，条件就不会满足。

如何让它等待结果值？

Answer 1

因为您想使用 async/await 和 node-sqlite3 (sqlite3) library does not support the Promise API, you need to use the node-sqlite (sqlite) 库，它是 sqlite3 的包装器并添加了对 Promise API 的支持。然后，您的代码将如下所示：

const sqlite3 = require('sqlite3');
const { open } = require('sqlite');

async function main() {
    try {
        sqlite3.verbose();
        const ordersDb = await createDbConnection('./ProcessedOrders.db');
        const orderProcessed = await orderAlreadyProcessed(ordersDb, "555");
        console.log("orderProcessed = " + orderProcessed);
        if (!orderProcessed) {
            console.log("So condition is met!");
        }
    } catch (error) {
        console.error(error);
    }
}


async function orderAlreadyProcessed(ordersDb, orderNumberStr) {
    try {
        console.log('Starting orderAlreadyProcessed function');
        const query = 'SELECT COUNT(SoldOrderNumber) as `recsCount` from ProcessedSoldOrders where SoldOrderNumber = ?;'
        const row = await ordersDb.get(query, [orderNumberStr]);
        console.log('Row with count =', row);
        console.log('row.recsCount =', row.recsCount);
        const result = typeof row !== 'undefined' && row.recsCount > 0;
        console.log('Returning ' + result);
        return result;
    } catch (error) {
        console.error(error);
        throw error;
    }
}

function createDbConnection(filename) {
    return open({
        filename,
        driver: sqlite3.Database
    });
}

main();

我特意没有去掉你的console.log等部分代码，以免混淆你程序的原有逻辑。

无法在 Node.js 中等待 sqlite3.Database.get() 函数完成

Cannot await for sqlite3.Database.get() function completion in Node.js

javascript

asynchronous

node.js

async-await

node-sqlite3