mysql 对行进行分组和排序

mysql group and order rows

我关注 table 'persons' 同一个人在不同的行

id |   firstname   |   surname   | date_created
------------------------------------------------------
3  | Nelli         | Schaller    | 2017-08-22 20:57:19
------------------------------------------------------
4  | Carl          | Schaller    | 2019-06-21 08:29:45
------------------------------------------------------
48 | Nelli         | Schaller    | 2020-06-25 13:06:09
------------------------------------------------------   
49 | Carl          | Schaller    | 2020-06-25 13:06:09

我要获取的都是id最大/最新date_created值的唯一Schallers

我试过了

SELECT id, CONCAT(surname, ", ", firstname) AS person, date_created
FROM persons
WHERE
surname LIKE "schall%"
GROUP by firstname, surname 
ORDER BY date_createdDESC, surname ASC LIMIT 0, 10

但仅按预期获得前两个条目(id 3 和 4),但我需要 48 和 49。 正如一些评论中提到的,在这种情况下,LIKE 语句不是必需的,但在现实生活中它将成为自动完成字段的来源,所以我需要 LIKE 知道如何管理吗?

您可以将子查询与组一起使用以获得最大 ID

select t.max_id, t.person, m.date_created
from (
    SELECT max(id) max_id, CONCAT(surname, ", ", firstname) AS person
    FROM persons
    WHERE surname LIKE "schall%"
    ORDER BY date_createdDESC, surname ASC 
    GROUP BY CONCAT(surname, ", ", firstname)

    ) t 
    inner join  persons m ON  CONCAT(m.surname, ", ", m.firstname) = t.person
        and m-id = t.max_id

使用NOT EXISTS:

SELECT p.id, CONCAT(p.surname, ', ', p.firstname) AS person, p.date_created
FROM persons p
WHERE p.surname LIKE '%schall%'
AND NOT EXISTS (SELECT 1 FROM persons WHERE firstname = p.firstname AND surname = p.surname AND id > p.id)
ORDER BY p.date_created DESC, person

如果选择每组最新的条件是date_created列则更改:

...AND id > p.id

...AND date_created > p.date_created
SELECT p.*
FROM persons p
LEFT JOIN persons p2 ON p2.firstname = p.firstname 
    AND p2.lastname = p.lastname
    AND p2.date_created > p.date_created
WHERE p2.id IS NULL

这是 SQL 服务器语法,但 MySQL 可能相似。

我假设你的 id 字段不需要像 date_created 一样检查,因为它是一个标识列,并且对于后者创建的记录来说无论如何都会更大,但显然根据您的实际数据进行调整。