使用 JPA、Kotlin 和 @ElementCollection 重新创建 table
Recreating table using JPA, Kotlin and @ElementCollection
我有一个奇怪的问题。这是我的代码:
@Table(name = "rank")
@Entity
data class Rank(
@Id
private val id: String,
@Embedded
private var rankValue: RankValue,
@ElementCollection
@CollectionTable(
name="rank_change",
joinColumns = [JoinColumn(name = "rank_id")]
)
private val set: MutableSet<RankChange>
) {
fun calculateDifference(loseRank: Rank, rankPolicy: RankPolicy): Double {
return rankPolicy.calculateRankDifference(rankValue.value, loseRank.rankValue.value)
}
fun addChange(difference: Double, now: LocalDateTime, sparringId: String? = null) {
rankValue = rankValue.apply(difference)
set.add(RankChange(date = now, value = difference, sparringId = sparringId))
}
}
@Embeddable
data class RankChange(
@Column(name = "date")
private val date: LocalDateTime,
@Column(name = "value")
private val value: Double,
@Column(name = "sparring_id")
private val sparringId: String? = null
)
当我向 MutableSet<RankChange>
添加元素时,hibernate 会删除“rank_change” table 并逐行插入。也许我应该实施 equals 和哈希码合同或使用 MutableList<T>
并添加 @OrderColumn
注释?但我真的不需要订单。
@ElementCollection
的行为类似于单向 @OneToMany
在这个意义上它会删除所有行并从内存中的集合中逐一插入元素。
为避免这种情况,您可以创建一个单独的实体来保存元素并使 (@OneToMany
- @ManyToOne
) 关系双向(mappedBy
在父端,@JoinColumn
在子端)。
我有一个奇怪的问题。这是我的代码:
@Table(name = "rank")
@Entity
data class Rank(
@Id
private val id: String,
@Embedded
private var rankValue: RankValue,
@ElementCollection
@CollectionTable(
name="rank_change",
joinColumns = [JoinColumn(name = "rank_id")]
)
private val set: MutableSet<RankChange>
) {
fun calculateDifference(loseRank: Rank, rankPolicy: RankPolicy): Double {
return rankPolicy.calculateRankDifference(rankValue.value, loseRank.rankValue.value)
}
fun addChange(difference: Double, now: LocalDateTime, sparringId: String? = null) {
rankValue = rankValue.apply(difference)
set.add(RankChange(date = now, value = difference, sparringId = sparringId))
}
}
@Embeddable
data class RankChange(
@Column(name = "date")
private val date: LocalDateTime,
@Column(name = "value")
private val value: Double,
@Column(name = "sparring_id")
private val sparringId: String? = null
)
当我向 MutableSet<RankChange>
添加元素时,hibernate 会删除“rank_change” table 并逐行插入。也许我应该实施 equals 和哈希码合同或使用 MutableList<T>
并添加 @OrderColumn
注释?但我真的不需要订单。
@ElementCollection
的行为类似于单向 @OneToMany
在这个意义上它会删除所有行并从内存中的集合中逐一插入元素。
为避免这种情况,您可以创建一个单独的实体来保存元素并使 (@OneToMany
- @ManyToOne
) 关系双向(mappedBy
在父端,@JoinColumn
在子端)。