如何检查数组中的单词的多个值

Question

我的标题可能有点混乱，抱歉。不知道该说什么。

我有一个工作示例，我试图缩短它，但我不知道怎么做。

function pigIt(str){
  let words = str.split(" ")
  let result = []
 for (let word of words) {
   
   if (word === "!"  ){
     result.push(word)
   }
     else if (word === "?"  ){
     result.push(word)
   }
     else if (word === "."  ){
     result.push(word)
   }
     else if (word === ","  ){
     result.push(word)
   }
   

   else if (word.indexOf("?") > -1){
  result.push(word.slice(1, word.length-1) + word[0] + "ay" +word[word.length-1])}
  else if (word.indexOf("!") > -1){
  result.push(word.slice(1, word.length-1) + word[0] + "ay" +word[word.length-1])}
  else if (word.indexOf(",") > -1){
  result.push(word.slice(1, word.length-1) + word[0] + "ay" +word[word.length-1])}
 else if (word.indexOf(".") > -1){
  result.push(word.slice(1, word.length-1) + word[0] + "ay" +word[word.length-1])}
 else result.push(word.slice(1,word.length) + word[0] + "ay")
 }
 return result.join(" ")
}


console.log(pigIt("Hello world")) // returns elloHay orldway
console.log(pigIt("Hello world !")) // returns elloHay orldway!
console.log(pigIt("Hello world, what a beautiful day.")) // returns elloHay orldway, hatway aay eautifulbay ayday.
console.log(pigIt("How are you? I am doing good!")) // returns owHay reaay ouyay? Iay maay oingday oodgay!

在这个例子中，如果是“!”、“?”、“、”或“.”，我该如何检查一行？包含在单词中？下面的 indexOf 也有同样的问题。

谢谢！

Answer 1

使用.match并使用正则表达式：

if (word.match(/[!?,.]/) {
    result.push(word)
}

Answer 2

尝试使用Regex过滤掉下面的特殊字符

const input = [
 "Hello world", // returns elloHay orldway
 "Hello world !", // returns elloHay orldway !
 "Hello world, what a beautiful day.", // returns elloHay orldway, hatway aay eautifulbay ayday.
 "How are you? I am doing good!" // // returns owHay reaay ouyay? Iay maay oingday oodgay!
];

const result = input.map(item => item.split(/\s+/).map(word => {
    const matchedVal = word.match(/[,.!?]$/g);
    return matchedVal ? 
      word.length === 1 ? word :
      `${word.substring(1, word.length - 1)}${word.charAt(0)}ay${matchedVal[0]}` : `${word.substring(1)}${word.charAt(0)}ay`
}).join(" "));

console.log(result);

Answer 3

尝试使用 some 和 includes 方法

function pigIt(str) {
  const words = str.split(" ");
  const result = [];
  for (let word of words) {
    if (["!", "?", ".", ","].some((char) => word.includes(char))) {
      word.length > 1
        ? result.push(
            word.slice(1, word.length - 1) +
              word[0] +
              "ay" +
              word[word.length - 1]
          )
        : result.push(word);
    } else {
      result.push(word.slice(1) + word[0] + "ay");
    }
  }
  return result.join(" ");
}

console.log(pigIt("Hello world")); // returns elloHay orldway
console.log(pigIt("Hello world !")); // returns elloHay orldway!
console.log(pigIt("Hello world, what a beautiful day.")); // returns elloHay orldway, hatway aay eautifulbay ayday.
console.log(pigIt("How are you? I am doing good!")); // returns owHay reaay ouyay? Iay maay oingday oodgay!

如何检查数组中的单词的多个值

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