如何将列表值与单个 csv 文件的行相匹配？

Question

我需要将整数值列表与 CVS 文件中的一行进行比较，以便找到与该值匹配的行。

'''

firstScore = 90  
secondScore = 80  
thirdScore = 75  

list = [firstScore, secondScore, thirdScore]

'''

csv 数据为：

    Name,first,second,third
    Paul,40,60,30
    Kevin,90,80,75
    Jenny,80,75,90

实际输出应该是匹配3个值的名字：Kevin.

Answer 1

欢迎来到 Whosebug :) 你能试试这个吗？

import csv

list = [firstScore, secondScore, thirdScore]

with open('test.csv', 'rt') as f:
reader = csv.reader(f, delimiter=',')

# skip the header of your csv
next(reader)

for row in reader:
  if((list[0] == int(row[1])) and (list[1] == int(row[2])) and (list[2] == int(row[3]))):
    # print name (present in first column -> index 0 of the row) 
    print(row[0])
    break
  else:
    print("No match found..")

我不是 Python 方面的专家，但如果它有效，请毫不犹豫地接受作为答案:)

如何将列表值与单个 csv 文件的行相匹配？

How can I match a list value to a single csv file's row?

csv

list

matching

python-3.x