AWS SAM 启动本地 api returns "Function name is required" 错误

Question

我们正在使用 CDK 来构建我们的基础架构配置。此外，如果有帮助，我会使用 cdk synth <stack_name> --no-staging > template.yml 为 SAM 创建 template.yml。我正在使用 AWS Toolkit invoke/debug 我在 Intellij 上的 lambda 函数，它工作正常。但是，如果我运行 sam local start-api 在终端上向我的一个函数发送请求，那么它 returns 堆栈跟踪错误；

Traceback (most recent call last):
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py", line 2317, in wsgi_app
    response = self.full_dispatch_request()
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py", line 1840, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py", line 1743, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/_compat.py", line 36, in reraise
    raise value
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py", line 1838, in full_dispatch_request
    rv = self.dispatch_request()
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py", line 1824, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/local/apigw/local_apigw_service.py", line 203, in _request_handler
    self.lambda_runner.invoke(route.function_name, event, stdout=stdout_stream_writer, stderr=self.stderr)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/commands/local/lib/local_lambda.py", line 84, in invoke
    function = self.provider.get(function_name)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/lib/providers/sam_function_provider.py", line 65, in get
    raise ValueError("Function name is required")
ValueError: Function name is required

这是我的命令运行

sam local start-api --env-vars env.json --docker-network test

给出输出

Mounting None at http://127.0.0.1:3000/v1 [GET, OPTIONS, POST]
Mounting None at http://127.0.0.1:3000/v1/user [GET, OPTIONS, POST]
You can now browse to the above endpoints to invoke your functions. You do not need to restart/reload SAM CLI while working on your functions, changes will be reflected instantly/automatically. You only need to restart SAM CLI if you update your AWS SAM template
2020-08-22 16:32:46  * Running on http://127.0.0.1:3000/ (Press CTRL+C to quit)
2020-08-22 16:33:03 Exception on /v1/user [OPTIONS]

这里是 env.json 我用作函数的环境变量

{
  "tenantGetV1Function54F63CB9": {
    "db": "alpha",
    "connectionString": "mongodb://mongo"
  },
  "tenantPostV1FunctionA56822D0": {
    "db": "alpha",
    "connectionString": "mongodb://mongo"
  },
  "userGetV1Function7E6E55C2": {
    "db": "alpha",
    "connectionString": "mongodb://mongo"
  },
  "userPostV1FunctionEB035EB0": {
    "db": "alpha",
    "connectionString": "mongodb://mongo"
  }
}

我也在运行ning Docker macOS 操作系统上的桌面。

编辑：在这里您可以找到简化的 template.yml，只有一个端点（一个函数定义）用于 tenantGetV1Function54F63CB9 函数。它将映射到 GET /v1 端点。我不希望包括 4 个函数的整个模板，这使大约一千行 .yml 代码。

https://gist.github.com/flexelem/d887136484d508e313e0a745c30a2d97

Answer 1

如果我通过在 CDK 中传递 Function 实例而不是它的 Alias 实例来创建 LambdaIntegration，问题就解决了。因此，我们正在创建带有别名的 lambda。然后，我们将别名从 Api 网关传递给它们关联的 Resource 实例。

这就是创作的方式；

Function tenantGetV1Function = Function.Builder.create(this, "tenantGetV1Function")
    .role(roleLambda)
    .runtime(Runtime.JAVA_8)
    .code(lambdaCode)
    .handler("com.yolda.tenant.lambda.GetTenantHandler::handleRequest")
    .memorySize(512)
    .timeout(Duration.minutes(1))
    .environment(environment)
    .description(Instant.now().toString())
    .build();

Alias tenantGetV1Alias = Alias.Builder.create(this, "tenantGetV1Alias")
    .aliasName("live")
    .version(tenantAdminGetV1Function.getCurrentVersion())
    .provisionedConcurrentExecutions(provisionedConcurrency)
    .build();

Resource v1Resource = v1Resource.addResource("{tenantId}");
v1Resource.addMethod("GET", LambdaIntegration.Builder.create(tenantGetV1Alias).build(), options);

如果我将 tenantGetV1Alias 替换为 tenantGetV1Function，则 sam build 命令会成功构建所有函数，这些函数将使 sam local start-api 启动它们。

Resource v1Resource = v1Resource.addResource("{tenantId}");
v1Resource.addMethod("GET", LambdaIntegration.Builder.create(tenantGetV1Function).build(), options);

如果我们分配别名，SAM 无法从 CloudFormation 模板中获取函数名称属性。

AWS SAM 启动本地 api returns "Function name is required" 错误

AWS SAM starting local api returns "Function name is required" error

amazon-web-services

aws-sam-cli

aws-sam