石英固定次数

Question

我有以下 spring 石英配置。当我每分钟都被解雇时，它工作得很好。现在我需要将这个工作解雇固定次数（特别是 2 次）。我该如何修改我的代码来执行此操作？

@Bean
public SchedulerFactoryBean schedulerFactoryBeanJobOne() {
    schedulerFactoryBean = new SchedulerFactoryBean();
    schedulerFactoryBean.setAutoStartup(false);
    schedulerFactoryBean.setTriggers(procesoJobOneTrigger().getObject());
    schedulerFactoryBean.setJobDetails(procesJobOne().getObject());
    schedulerFactoryBean.setJobFactory(springBeanJobFactory());
    return schedulerFactoryBean;
}

@Bean
public SpringBeanJobFactory springBeanJobFactory() {
    return new AutowiringSpringBeanJobFactory();
}

@Bean
public JobDetailFactoryBean procesJobOne() {
    JobDetailFactoryBean jobDetailFactory = new JobDetailFactoryBean();
    jobDetailFactory.setJobClass(JobOne.class);
    jobDetailFactory.setGroup("quartz");
    return jobDetailFactory;
}

@Bean
public CronTriggerFactoryBean procesoJobOneTrigger() {
    CronTriggerFactoryBean cronTriggerFactoryBean = new CronTriggerFactoryBean();
    cronTriggerFactoryBean.setJobDetail(procesJobOne().getObject());
    // Runs every 60secs
    cronTriggerFactoryBean.setCronExpression("0/60 * * * * ?");
    cronTriggerFactoryBean.setGroup("quartz");
    return cronTriggerFactoryBean;
}

Answer 1

您的 cron 表达式是您提供作业应该运行

的次数的地方

 # * * * * *  command to execute
 # │ │ │ │ │
 # │ │ │ │ │
 # │ │ │ │ └───── day of week (0 - 6) (0 to 6 are Sunday to Saturday)
 # │ │ │ └────────── month (1 - 12)
 # │ │ └─────────────── day of month (1 - 31)
 # │ └──────────────────── hour (0 - 23)
 # └───────────────────────── min (0 - 59)

你可以使用这个：

# m   h   dom mon dow  
  0  14,15 *   *   *

你的工作将运行在 14:00 和 15:00 即两次

石英固定次数

quartz fixed number of times

java

quartz-scheduler