PHP Preg Replace 删除部分字符串
PHP Preg Replace to remove part of string
我想使用 preg_replace 从字符串中删除一部分,我搜索了很长时间,但找不到帮助我做出正确表达的方法。
字符串:
test test test test test test test test test test test test test test test test test test test test test test test test
<div>[[{"fid":"1915134","view_mode":"default","type":"media","attributes": {"height":360,"width":480,"alt":"#some text here","class":"media-element file-default"}}]]</div>
test test test test test test test test test test test test test testtest test test test test test test test test test
test test test test test test test test test test test test
删除以[[{"fid":"
开始并以}}]]
结束的部分
你可以使用这个:
$a = preg_replace('/\[\[{"fid"[^}\]]+}}\]\]/','',$a);
我想使用 preg_replace 从字符串中删除一部分,我搜索了很长时间,但找不到帮助我做出正确表达的方法。 字符串:
test test test test test test test test test test test test test test test test test test test test test test test test
<div>[[{"fid":"1915134","view_mode":"default","type":"media","attributes": {"height":360,"width":480,"alt":"#some text here","class":"media-element file-default"}}]]</div>
test test test test test test test test test test test test test testtest test test test test test test test test test
test test test test test test test test test test test test
删除以[[{"fid":"
开始并以}}]]
结束的部分
你可以使用这个:
$a = preg_replace('/\[\[{"fid"[^}\]]+}}\]\]/','',$a);