Java 带十进制转换的 BigDecimal long

Question

我的 BigDecimal 值为 123.45。我想将其转换为 12345 的 long 值，我想知道这样做的最佳方法是什么。

我宁愿避免做类似的事情 val.multiply(new BigDecimal(100)).toBigInteger()

Answer 1

用于BigDecimal字符串和字符串替换“.”并做一个 Long.valueOf

Answer 2

只是张贴这个以防你想知道。进行了性能测试，正如预期的那样，字符串替换性能最差。

结果： movePointRight：1230 相乘：833 scaleByPowerOfTen：591 字符串替换：3289

    BigDecimal val = new BigDecimal(0);
    long start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.movePointRight(2);
    }
    long end = System.currentTimeMillis();
    System.out.println("movePointRight: " + (end - start));

    BigDecimal ten = new BigDecimal(10);
    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.multiply(new BigDecimal(100));
    }

    end = System.currentTimeMillis();
    System.out.println("multiply: " + (end - start));

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.scaleByPowerOfTen(2);
    }

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.scaleByPowerOfTen(2);
    }
    end = System.currentTimeMillis();
    System.out.println("scaleByPowerOfTen: " + (end - start));

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val =  new BigDecimal(d.toString().replace(".", ""));
    }
    end = System.currentTimeMillis();
    System.out.println("String replacement: " + (end - start));

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