如何使用 scrapy-splash 从该网站获取动态加载的内容?

How to get dinamically-loaded content from this website using scrapy-splash?

我正在尝试使用 scrapy-splash 从这个 website 获取数据,但我无法提取数据。我想获取有关每个真实状态的数据,如 href、价格等。这是我的代码:

setings.py:

ROBOTSTXT_OBEY = False

USER_AGENT = "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/34.0.1847.131 Safari/537.36"

SPLASH_ENABLED = True


DOWNLOADER_MIDDLEWARES = {
    'scrapy_splash.SplashCookiesMiddleware': 723,
    'scrapy_splash.SplashMiddleware': 725,
    'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810,
}

SPLASH_URL = 'http://localhost:8050/'

SPIDER_MIDDLEWARES = {
    'scrapy_splash.SplashDeduplicateArgsMiddleware': 100,
}

DUPEFILTER_CLASS = 'scrapy_splash.SplashAwareDupeFilter'
HTTPCACHE_STORAGE = 'scrapy_splash.SplashAwareFSCacheStorage'

我的蜘蛛:

class M2Spider(scrapy.Spider):
    
    name = "m2"
    allowed_domains = ['metrocuadrado.com']
    start_urls = [
            'https://www.metrocuadrado.com/bodega/arriendo'
            ]
    
    def start_requests(self):
        for url in self.start_urls:
            yield SplashRequest(url=url,callback= self.parse, 
                               endpoint='render.html',
                               args={'wait': 10},)
                  
    def parse(self, response):
        print("--------------------------------------------------------------")
        real_states= response.selector.xpath(".//a[@class='sc-bdVaJa ebNrSm']").getall()

        print("real_states")

输出打印是一个空列表[]。我是新手。有什么建议吗?

我会做的是:

https://www.metrocuadrado.com/results/_next/static/chunks/commons.8afec6af6d5add2097bf.js 发送请求,如果您搜索“X-Api-Key”,您会在响应中找到 API-key。这样就可以使用正则表达式轻松提取,例如:re.findall(r'"X-Api-Key":"(\w+)"').

然后,当您提取了 API 密钥后,向 https://www.metrocuadrado.com/rest-search/search?seo=/bodega/arriendo&from=0&size=50 发送请求,这是您发送的网站中隐藏的 API。要获得有效回复,您必须像这样附加 header

scrapy.Request(
    url=url_variable,
    headers={
        "x-api-key": api_key_variable_from_prev_step
    }
)

从 API 你得到 JSON 格式的数据,这通常比解析 html 更可靠,因为它经常改变。