Error - ValueError: The number of weights does not match the population in python 3

Question

我在 python 中编写了一个代码来制作一个简单的井字游戏，但错误不断出现。我无法弄清楚问题..请帮忙

该代码在第一种情况下工作正常，但我不知道为什么它不是

您可以在任何编辑器上查看代码 -

    import random
    from random import choices
    board = [1, 2, 3, 4, 5, 6, 7, 8, 9]
    weights = [0.1, 0.05, 0.1, 0.05, 0.3, 0.05 , 0.1, 0.05, 0.1]
    _board = [1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9]
    
    def choose_random():
        return(choices(board,weights))
    
    def draw():
        print(_board[0], _board[1], _board[2])
        print(_board[3], _board[4], _board[5])
        print(_board[6], _board[7], _board[8])
    
    def user_chance():
        draw()
        choice = int(input('Choose any of the block: '))
        board.remove(choice)
        index = _board.index(choice)
        _board[index] = "X"
        comp_chance()    
    
    def comp_chance():
        if(len(board) == 0):
            print("It's a tie !")
        else:
            random = choose_random()
            board.remove(random)
            index = _board.index(random)
            _board[index] = 'O'
            user_chance()
        
    user_chance()

Answer 1

在第 17 行中，当您调用 choose_random() 时，棋盘列表和权重列表的长度不匹配，因此您会收到错误消息。

Answer 2

这里有几个问题需要解决：

您正在从 board 列表而不是 weights 列表中删除值，因此您遇到了这个问题
choose_random() 是 return 一个 k 值的列表，你没有指定 k 所以它会 return具有一个值的列表。您应该在 return 语句的末尾添加 [0]。

您还应该添加检查用户是否在板上输入了有效位置，否则，您将收到 value is not in list

的错误

from random import choices
board = [1, 2, 3, 4, 5, 6, 7, 8, 9]
weights = [0.1, 0.05, 0.1, 0.05, 0.3, 0.05 , 0.1, 0.05, 0.1]
_board = [1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9]

def choose_random():
    return(choices(board,weights))[0]

def draw():
    print(_board[0], _board[1], _board[2])
    print(_board[3], _board[4], _board[5])
    print(_board[6], _board[7], _board[8])

def user_chance():
    draw()
    choice = int(input('Choose any of the block: '))
    board.remove(choice)
    index = _board.index(choice)
    del weights[index]
    _board[index] = "X"
    comp_chance()    

def comp_chance():
    if(len(board) == 0):
        print("It's a tie !")
    else:
        random = choose_random()
        board.remove(random)
        index = _board.index(random)
        del weights[index]
        _board[index] = 'O'
        user_chance()

user_chance()

Answer 3

我评论了我所做的更改：

import random
from random import choices
board = ["1", "2", "3", "4", "5", "6", "7", "8", "9"] #Changed to strings
weight_values = {"1": 0.1,
                 "2": 0.05,
                 "3": 0.1,
                 "4": 0.05,
                 "5": 0.3,
                 "6": 0.05,
                 "7": 0.1,
                 "8": 0.05,
                 "9": 0.1} #Now a dictionary
_board = [1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9]

def choose_random():
    return(choices(board,list(weight_values.values()))) #weight_values.values() returns a list of the weights, which is needed for this function

def draw():
    print(_board[0], _board[1], _board[2])
    print(_board[3], _board[4], _board[5])
    print(_board[6], _board[7], _board[8])

def user_chance():
    draw()
    
    choice = (input('Choose any of the block: '))
    
    board.remove(choice) #Remove from board[]
    del weight_values[choice] #Remove from weight_values{}
    
    index = _board.index(int(choice))
    _board[index] = "X"
    comp_chance()    

def comp_chance():
    if(len(board) == 0):
        print("It's a tie !")
    else:
        random = choose_random()

        board.remove(str(random[0]))  #Remove from board[]    
        index = _board.index(int(random[0]))
        
        del weight_values[str(random[0])] #Remove from weight_values{}
        _board[index] = 'O'
        user_chance()
    
user_chance()

玩家仍然可以选择已标记的方块，因此需要修复。问题是您在删除板值时没有删除权重值。权重值和板值的数量必须相同。作为字典，管理起来就方便多了。

Error - ValueError: The number of weights does not match the population in python 3

Error - ValueError: The number of weights does not match the population in python 3

python

tic-tac-toe

python-3.x