Curly curly passing a column name to mutate or regex_left_join returns 错误，找不到赋值运算符`:=`

Question

我在控制台中遇到错误：

错误 :=({ : 找不到函数 ":="

我只使用 fuzzyjoin（David Robinson 的）和 tidyverse 包。该函数被接受，没有语法错误。在执行时，错误被抛出给我。可能是什么原因？

 df_recode_brand_name <- 
    tibble(
      regex_name  = c("wacoal|tempt", "calvin", "hanky", "victoria"),
      return_name = c("wacoal",       "calvin", "hanky", "victoria"))
  
  df_recode_product_category <- 
    tibble(
      regex_name  = c("lingerie", "pant", "bra", "undies"),
      return_name = c("lingerie", "pant", "bra", "undies"))
  
  
fn_regex_recode <- function(df, df_recode_dic, col_name) {
    df %>% regex_left_join(
      df_recode_dic, 
      by = c({{col_name}} := "regex_name"),
      ignore_case = T ) %>% 
    mutate({{col_name}} := if_else(is.na(return_name), str_to_lower({{col_name}}), return_name)) %>% 
    select(-regex_name, -return_name)  
  }

df_raw2 <-  
    df_raw %>%  
    fn_regex_recode(df_recode_brand_name,brand_name) %>% 
    fn_regex_recode(df_recode_product_category, product_category)

这是示例数据

df_raw <-
tibble::tribble(
                ~brand_name,                                  ~product_category,           ~description,
             "Calvin Klein",              "Women - Lingerie & Shapewear - Bras", "Practice bold, fearl",
                   "Wacoal",                                             "Bras", "Beautiful all over c",
        "Victoria's Secret",                           "Add-2-Cups Push-Up Bra", "The ultimate lift-lo",
                   "Wacoal",     "Women - Lingerie & Shapewear - Sexy Lingerie", "With luscious lace a",
        "Victoria's Secret",                 "Incredible by Victoria Sport Bra", "Tackle high-intensit",
             "Calvin Klein", "Women - Lingerie & Shapewear - Designer Lingerie", "Moderate coverage th",
        "Victoria's Secret",                        "Wicked Unlined Uplift Bra", "A little lift goes a",
        "Victoria's Secret",                     "Crochet Lace Cheekster Panty", "The prettiest croche",
        "Victoria's Secret",                           "Curved-hem Thong Panty",  "Seriously sleek and",
        "Victoria's Secret",                           "Add-2-Cups Push-Up Bra", "The ultimate lift-lo",
        "Victoria's Secret",                             "Perfect Coverage Bra", "Our fullest coverage",
               "US TOPSHOP",                                         "Lingerie", "Revamp your lingerie",
             "Calvin Klein",                                        "Sleepwear", "a modern cotton loun",
                    "AERIE",           "Everyday Loves Undies 7 for .50 USD", "Introducing Everyday",
      "b.tempt'd by Wacoal", "Women - Lingerie & Shapewear - Designer Lingerie",  "Sheer and sexy, the",
                   "Wacoal",              "Women - Lingerie & Shapewear - Bras", "Discover the glove-l",
   "Victoria's Secret Pink",                      "Wear Everywhere Push-Up Bra", "An everyday fave wit",
                   "WACOAL",                                          "PANTIES", "A sheer lace panty t",
        "Victoria's Secret",                          "Add-1?-Cups Push-Up Bra", "This push-up gives y",
                   "Wacoal",                                             "Bras", "Sport bra offers gre"
  )

Answer 1

尝试在 by 中使用 setNames 来传递命名向量。

library(dplyr)
library(fuzzyjoin)
library(rlang)

  fn_regex_recode <- function(df, df_recode_dic, col_name) {
    val <- deparse(substitute(col_name))
    df %>% 
      regex_left_join(
        df_recode_dic, 
        by = setNames('regex_name', val),ignore_case = TRUE) %>%
      mutate({{col_name}} := if_else(is.na(return_name), str_to_lower({{col_name}}), return_name)) %>% 
      select(-regex_name, -return_name) 
  }

Curly curly passing a column name to mutate or regex_left_join returns 错误，找不到赋值运算符`:=`

Curly curly passing a column name to mutate or regex_left_join returns error, could not find assignment operator `:=`

r

tidyverse

fuzzyjoin

tidyeval