如何省略外部 XML 元素的名称

Question

我需要生成 XML 个这样的文件：

  <package>
    <dc:contributor id="creator1">John Doe</dc:contributor>
    <meta refines="creator1" property="role" scheme="marc:relators">aut</meta>
    <meta refines="creator1" property="role" scheme="onix:codelist17">A01</meta>
    <meta refines="creator1" property="file-as">Doe, John</meta>
    <meta refines="creator1" property="diplay-seq">1</meta>
    <dc:contributor id="reviewer1">Mary Poppins</dc:contributor>
    <meta refines="reviewer1" property="role" scheme="marc:relators">rev</meta>
    <meta refines="reviewer1" property="file-as">Poppins, Mary</meta>
    <meta refines="reviewer1" property="diplay-seq">1</meta>
    <dc:contributor id="translator1">Alfred Weasley</dc:contributor>
    <meta refines="translator1" property="role" scheme="marc:relators">trl</meta>
    <meta refines="translator1" property="role" scheme="onix:codelist17">B06</meta>
    <meta refines="translator1" property="file-as">Weasley, Alfred</meta>
    <meta refines="translator1" property="diplay-seq">1</meta>
  </package>

这里的顺序很重要。

我使用这个结构：

type Pack struct {
    XMLName struct{}        `xml:"package"`
    People  []PersonWrapper `xml:""` // <-- is this the problem?
}

type Person struct {
    Id       string `xml:"id,attr"`
    Name     string `xml:"-"`
    Surname  string `xml:"-"`
    FullName string `xml:",innerxml"`
}

type Meta struct {
    Refines  string `xml:"refines,attr"`
    Property string `xml:"property,attr"`
    Scheme   string `xml:"scheme,attr,omitempty"`
    Value    string `xml:",innerxml"`
}

type PersonWrapper struct {
    Person Person `xml:"dc:contributor"`
    Metas  []Meta `xml:"meta"`
}

有了这个我得到了：

<package>
  <People>
    <dc:contributor id="creator1">John Doe</dc:contributor>
    <meta refines="creator1" property="role" scheme="marc:relators">aut</meta>
    <meta refines="creator1" property="role" scheme="onix:codelist17">A01</meta>
    <meta refines="creator1" property="file-as">Doe, John</meta>
    <meta refines="creator1" property="diplay-seq">1</meta>
  </People>
  <People>
    <dc:contributor id="reviewer1">Mary Poppins</dc:contributor>
    <meta refines="reviewer1" property="role" scheme="marc:relators">rev</meta>
    <meta refines="reviewer1" property="file-as">Poppins, Mary</meta>
    <meta refines="reviewer1" property="diplay-seq">1</meta>
  </People>
  <People>
    <dc:contributor id="translator1">Ben Weasley</dc:contributor>
    <meta refines="translator1" property="role" scheme="marc:relators">trl</meta>
    <meta refines="translator1" property="role" scheme="onix:codelist17">B06</meta>
    <meta refines="translator1" property="file-as">Weasley, Ben</meta>
    <meta refines="translator1" property="diplay-seq">1</meta>
  </People>
</package>

如何去除 <People/> 外标签？我试图将内部结构包装到更高级别的其他结构中，但无法达到所需的结构。

Answer 1

您可以为 PersonWrapper 实现 xml.Marshaler 接口（并将 xmlnames 添加到嵌套结构）。

type Pack struct {
    XMLName struct{} `xml:"package"`
    People  []PersonWrapper
}

type Person struct {
    XMLName  xml.Name `xml:"dc:contributor"`
    Id       string   `xml:"id,attr"`
    Name     string   `xml:"-"`
    Surname  string   `xml:"-"`
    FullName string   `xml:",innerxml"`
}

type Meta struct {
    XMLName  xml.Name `xml:"meta"`
    Refines  string   `xml:"refines,attr"`
    Property string   `xml:"property,attr"`
    Scheme   string   `xml:"scheme,attr,omitempty"`
    Value    string   `xml:",innerxml"`
}

type PersonWrapper struct {
    Person Person `xml:"dc:contributor"`
    Metas  []Meta `xml:"meta"`
}

func (pw PersonWrapper) MarshalXML(e *xml.Encoder, start xml.StartElement) error {
    if err := e.Encode(pw.Person); err != nil {
        return err
    }
    if err := e.Encode(pw.Metas); err != nil {
        return err
    }
    return nil
}

https://play.golang.org/p/hzrBdHXHwOB

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