Mysql 提取 json 数据并搜索多个值

Mysql extract json data and search multiple values

您好,我有一个汽车列表网站,我想从 JSON 列中过滤多个值 data

我的数据库 table 如下所示:

id | label    | data
---|----------|---------------------------------
 1 | "test 1" | {"Year":"2014","Gear":"Auto"}
 2 | "test 2" | {"Year":"2010","Gear":"Manual"}
 3 | "test 3" | {"Year":"2009","Gear":"None"}

例如我想按齿轮过滤,“自动”或“手动”:

SELECT * FROM test WHERE 
JSON_EXTRACT(data, "$.Year") in (2010,2014) AND
JSON_EXTRACT(data, "$.Gear") in ("Auto","Manual")

当我为 Gear 添加过滤器时,查询 returns 结果为零,但 Year 的过滤器工作正常。

JSON_EXTRACT returns a JSON string,其中包括引号。您可以在搜索中包含此内容:

SELECT * FROM test
WHERE JSON_EXTRACT(data, "$.Year") in (2010,2014)
    AND JSON_EXTRACT(data, '$.Gear') IN ('"Manual"','"Auto"');

或使用the JSON_UNQUOTE function:

SELECT * FROM test
WHERE JSON_EXTRACT(data, "$.Year") in (2010,2014)
    AND JSON_UNQUOTE(JSON_EXTRACT(data, '$.Gear')) IN ('Manual','Auto');

请参阅此处 fiddle:https://www.db-fiddle.com/f/fC48mHEM1nuLUZCTP8CLfs/0

我推荐 json operator ->>,它结合了 JSON_EXTRACT()JSON_UNQUOTE():

select * 
from test
where data ->> '$.Year' in (2010, 2014) and data ->> '$.Gear' in ('Manual', 'Auto');

->> 已添加到 MySQL 5.7.13.