在 postgres 中递归提取 JSON 值
Extract JSON values recursivey in postgres
我有一些 JSON 数据存储在列中。我想解析 json 数据并针对特定键提取所有值。
这是我的示例数据:
{
"fragments": [
{
"fragments": [
{
"fragments": [
{
"fragments": [],
"fragmentName": "D"
},
{
"fragments": [],
"fragmentName": "E"
},
{
"fragments": [],
"fragmentName": "F"
}
],
"fragmentName": "C"
}
],
"fragmentName": "B"
}
],
"fragmentName": "A"
}
预期输出:
D, E, F, C, B, A
我想从上面的 JSON.
中提取所有 fragmentName 值
我浏览了以下堆栈,但没有发现任何有用的东西:
Postgres recursive query with row_to_json
已编辑:
这是我在上述堆栈上尝试过的一种方法:
WITH RECURSIVE key_and_value_recursive(key, value) AS (
SELECT
t.key,
t.value
FROM temp_frg_mapping, json_each(temp_frg_mapping.info::json) AS t
WHERE id=2
UNION ALL
SELECT
t.key,
t.value
FROM key_and_value_recursive,
json_each(CASE
WHEN json_typeof(key_and_value_recursive.value) <> 'object' THEN '{}' :: JSON
ELSE key_and_value_recursive.value
END) AS t
)
SELECT *
FROM key_and_value_recursive;
输出:
仅获得 0 级嵌套。
我会使用递归查询,但是 jsonb_array_elements()
:
with recursive cte as (
select id, info ->> 'fragmentName' as val, info -> 'fragments' as info, 1 lvl
from mytable
where id = 2
union all
select c.id, x.info ->> 'fragmentName', x.info -> 'fragments', c.lvl + 1
from cte c
cross join lateral jsonb_array_elements(c.info) as x(info)
where c.info is not null
)
select id, val, lvl
from cte
where val is not null
查询遍历对象深度优先;在这个过程的每一步,我们都取消嵌套 json 数组并检查片段名称是否可用。我们不需要检查返回值的类型:我们只使用标准函数,直到数据耗尽。
示例数据:
{
"fragments": [
{
"fragments": [
{
"fragments": [
{
"fragments": [
],
"fragmentName": "D"
},
{
"fragments": [
],
"fragmentName": "E"
},
{
"fragments": [
],
"fragmentName": "F"
}
],
"fragmentName": "C"
}
],
"fragmentName": "B"
}
],
"fragmentName": "A"
}
结果:
id | val | lvl
-: | :-- | --:
2 | A | 1
2 | B | 2
2 | C | 3
2 | D | 4
2 | E | 4
2 | F | 4
我有一些 JSON 数据存储在列中。我想解析 json 数据并针对特定键提取所有值。
这是我的示例数据:
{
"fragments": [
{
"fragments": [
{
"fragments": [
{
"fragments": [],
"fragmentName": "D"
},
{
"fragments": [],
"fragmentName": "E"
},
{
"fragments": [],
"fragmentName": "F"
}
],
"fragmentName": "C"
}
],
"fragmentName": "B"
}
],
"fragmentName": "A"
}
预期输出:
D, E, F, C, B, A
我想从上面的 JSON.
中提取所有 fragmentName 值我浏览了以下堆栈,但没有发现任何有用的东西:
已编辑:
这是我在上述堆栈上尝试过的一种方法:
WITH RECURSIVE key_and_value_recursive(key, value) AS (
SELECT
t.key,
t.value
FROM temp_frg_mapping, json_each(temp_frg_mapping.info::json) AS t
WHERE id=2
UNION ALL
SELECT
t.key,
t.value
FROM key_and_value_recursive,
json_each(CASE
WHEN json_typeof(key_and_value_recursive.value) <> 'object' THEN '{}' :: JSON
ELSE key_and_value_recursive.value
END) AS t
)
SELECT *
FROM key_and_value_recursive;
输出:
仅获得 0 级嵌套。
我会使用递归查询,但是 jsonb_array_elements()
:
with recursive cte as (
select id, info ->> 'fragmentName' as val, info -> 'fragments' as info, 1 lvl
from mytable
where id = 2
union all
select c.id, x.info ->> 'fragmentName', x.info -> 'fragments', c.lvl + 1
from cte c
cross join lateral jsonb_array_elements(c.info) as x(info)
where c.info is not null
)
select id, val, lvl
from cte
where val is not null
查询遍历对象深度优先;在这个过程的每一步,我们都取消嵌套 json 数组并检查片段名称是否可用。我们不需要检查返回值的类型:我们只使用标准函数,直到数据耗尽。
示例数据:
{
"fragments": [
{
"fragments": [
{
"fragments": [
{
"fragments": [
],
"fragmentName": "D"
},
{
"fragments": [
],
"fragmentName": "E"
},
{
"fragments": [
],
"fragmentName": "F"
}
],
"fragmentName": "C"
}
],
"fragmentName": "B"
}
],
"fragmentName": "A"
}
结果:
id | val | lvl -: | :-- | --: 2 | A | 1 2 | B | 2 2 | C | 3 2 | D | 4 2 | E | 4 2 | F | 4