Python简单的剪刀石头布游戏

Question

嘿，所以我是一名新手程序员，为了上学，我必须在 python 中制作一个简单的剪刀石头布游戏（3 个中最好的）。我的问题是分数系统，我收到以下两个错误：

Traceback (most recent call last):
  File "c:\Users\Fabian\OneDrive\School\Python\Project stuff\RockPaperScissors\game.py", line 66, in <module>
    game1()
  File "c:\Users\Fabian\OneDrive\School\Python\Project stuff\RockPaperScissors\game.py", line 26, in game1
    score_com = score_com + 1
UnboundLocalError: local variable 'score_com' referenced before assignment

这是我目前的代码：

import random

#variables
rock = 1
paper = 2
scissors = 3

#empty score
score = 0
score_com = 0

#game info
print("Rules and how to play: ")
print("The game is best out of 3")
print("If you wanna choose rock type 1, if you wanna choose paper type 2 and if you wanna use scissors type 3")
print("Dont worry if you forget what number represents what choice, there will be a reminder before you input a number")

#how the game works
def game1():
    
    choice = input("Choose: rock, paper or scissors (1, 2 or 3)")
    if choice == "1":
        choice_com = random.randint(1, 3)
        print(choice_com)

        if choice_com == 1:
            print("Tie!")
        if choice_com == 2:
            print("You lost!")
            score_com = score_com + 1
        if choice_com == 3:
            print("You win!")
            score = score + 1

    elif choice == "2":
        choice_com = random.randint(1, 3)
        print(choice_com)

        if choice_com == 1:
            print("You win!")
        if choice_com == 2:
            print("Tie!")
            score_com = score_com + 1
        if choice_com == 3:
            print("You lost!")
            score = score + 1

    elif choice == "3":
        choice_com = random.randint(1, 3)
        print(choice_com)

        if choice_com == 1:
            print("You lost!")
            score_com = score_com + 1
        if choice_com == 2:
            print("You won!")
            score = score + 1
        if choice_com == 3:
            print("Tie!")   
            
    
#the order of how things are supposed to be displayed and a simple way of seeing the score count
start = input("Start? y/n")
if start == "y":
    game1()
    print("Score player 1: ")
    print(score)
    print("Score player 2: ")
    print(score_com)
    game1()
    print("Score player 1: ")
    print(score)
    print("Score player 2: ")
    print(score_com)
    if score == 2:
        print("Player 1 wins!")
        exit()
    if score_com == 2:
        print("Player 2 wins!") 
        exit()  
    game1()
    print("Score player 1: ")
    print(score)
    print("Score player 2: ")
    print(score_com)
    if score == 3:
        print("Player 1 wins!")
    if score_com == 3:
        print("Player 2 wins!")
    if score == 2:
        print("Player 1 wins!")
    if score_com == 2:
        print("Player 2 wins!")

这个问题可能是一个非常简单的解决方法，但正如我所说，我是编程新手，所以我找不到解决方法。提前感谢任何帮助我的人！

Answer 1

一个简单的修复方法是在函数的开头添加以下行，以便它使用全局变量

def game1():
    global score
    global score_com

    ...

或者，您可以game1同时获取分数变量和return更新后的分数。

Answer 2

您的函数 game1 正在使用 local score_com 变量。
您应该在函数内部指明要使用全局变量。

def game1():
    global score_com

或引用全局变量作为参数

def game1(score_com=score_com):
   ...

同变量score

Answer 3

默认情况下 Python，假定函数更改的任何变量都是函数的局部变量。如果你想改变像 score_com 这样的全局变量，你需要在函数中添加一个 global score_com 声明。在这种情况下，您还要更新 score，因此也需要声明：

def game1():
    global score, score_com
    ...

Answer 4

感谢所有回复的人！

我在变量前面添加了全局变量，如下所示，效果很好。

def game1():
global score, score_com

下次我遇到类似情况时，我会牢记所有答案:D

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