在while循环中从用户输入中获取最小值

Question

我正在编写一个 Python 程序，它不断地向用户询问从 1 到 100 的数字，然后一旦用户输入数字 0，程序就会打印出提供的最小数字和最大数字，如以及所有数字的平均值。

我唯一的问题：当我想排除 0 时，我总是得到 0 作为输入的最小值。

我已经尝试过执行以下操作：

count = 0
total = 0
number = 1
smallest = 0
largest = 0

while number != 0:
    number = int(input("Please input a value from 1 to 100: "))
    
    if number < 0 or number > 100:
        print("Why you give me value outside of range :(\n")
        count -= 1
        continue
   
    count += 1
    total = total + number
    
    if number > largest:
        largest = number

if number == 0:
    count -= 1
    average = total / count
    if number < smallest:
        smallest = number
    print("The results are: ")
    print('Smallest: {}'.format(smallest))
    print('Largest: {}'.format(largest))
    print('Average: {}'.format(average))
    print("\nThank you!")

Answer 1

开头加smallest = 101即可，

if number < smallest:
    smallest = number

到你的while块，最后删除相同的代码。

此外，您的 count 已关闭，您应该删除两个减量 count -= 1 来解决这个问题。

您也可以删除 if number == 0:，因为您在 while 条件中已经有 while number != 0:，所以您知道它是零。

Answer 2

您需要在输入数字时同时跟踪最大和最小值。

在进行任何处理之前，我还检查了超出范围的数字：

count = 0
total = 0
number = 0
smallest = 101  # starts bigger than any input number
largest = 0     # starts smaller than any input number

while True:
    number = int(input("Please input a value from 1 to 100: "))
    if number == 0:
        break
    
    if number < 0 or number > 100:
        print("Why you give me value outside of range :(\n")
        continue
   
    count += 1
    total = total + number
    
    if number > largest:
        largest = number

    if number < smallest:
        smallest = number

if number == 0:
    average = total / count
    print("The results are: ")
    print('Smallest: {}'.format(smallest))
    print('Largest: {}'.format(largest))
    print('Average: {}'.format(average))
    print("\nThank you!")

Answer 3

这是另一个版本，这次使用列表来保存有效数字：

numbers = []

while True:
    number = int(input("Please input a value from 1 to 100: "))
    if number == 0:
        break
    
    if number < 0 or number > 100:
        print("Why you give me value outside of range :(\n")
        continue
   
    numbers.append(number)

if numbers:
    average = sum(numbers) / len(numbers)
    print("The results are: ")
    print('Smallest: {}'.format(min(numbers)))
    print('Largest: {}'.format(max(numbers)))
    print('Average: {}'.format(average))
    print("\nThank you!")

在while循环中从用户输入中获取最小值

Getting the minimum value from user input in a while loop

python

loops

minimum

conditional-statements