手动将误差线添加到 seaborn 线标记图
Add error bars manually to seaborn line marker plots
我有 x
、mean
和 std
列。我想用使用 seaborn 的标记绘制线:
import seaborn as sns
import matplotlib.pyplot as plt
x = [0,1,2]
mean = [2,1,3]
std = [0.1,0.4,0.2]
sns.lineplot(x=x,y=mean,marker='o')
如何添加 std
作为误差线?
来自 seaborn 文档,
markers : boolean, list, or dictionary, optional
Object determining how to draw the markers for different levels of the
``style`` variable. Setting to ``True`` will use default markers, or
you can pass a list of markers or a dictionary mapping levels of the
``style`` variable to markers. Setting to ``False`` will draw
marker-less lines. Markers are specified as in matplotlib.
markers
与 lineplot
的 style
选项配合使用。在你的情况下,使用 marker
,它被传递给 plt.plot
,而不是 markers
:
sns.lineplot(x=x,y=mean,marker='o')
输出:
我找到了适合我的答案:
df = pd.DataFrame({'x':x,'y':mean,'std':std})
g = sns.FacetGrid(df, size=5)
g.map(plt.errorbar, "x", "y", "std", marker="o")
我有 x
、mean
和 std
列。我想用使用 seaborn 的标记绘制线:
import seaborn as sns
import matplotlib.pyplot as plt
x = [0,1,2]
mean = [2,1,3]
std = [0.1,0.4,0.2]
sns.lineplot(x=x,y=mean,marker='o')
如何添加 std
作为误差线?
来自 seaborn 文档,
markers : boolean, list, or dictionary, optional
Object determining how to draw the markers for different levels of the
``style`` variable. Setting to ``True`` will use default markers, or
you can pass a list of markers or a dictionary mapping levels of the
``style`` variable to markers. Setting to ``False`` will draw
marker-less lines. Markers are specified as in matplotlib.
markers
与 lineplot
的 style
选项配合使用。在你的情况下,使用 marker
,它被传递给 plt.plot
,而不是 markers
:
sns.lineplot(x=x,y=mean,marker='o')
输出:
我找到了适合我的答案:
df = pd.DataFrame({'x':x,'y':mean,'std':std})
g = sns.FacetGrid(df, size=5)
g.map(plt.errorbar, "x", "y", "std", marker="o")