如何将两个单独的 sql 查询组合成两个单独的列?
How to combine two separate sql queries into two separate columns?
我正在元数据库中进行 SQL 数据库查询。我有两个单独的查询,我希望将它们输出为两个单独的列,按名称排序。在执行 union 之后,它似乎将所有值都放入一列中以复制名称。实现两列输出(每个查询一个)的最佳方法是什么?
SELECT "source"."name" AS "name", "source"."count" AS "count"
FROM (SELECT "source"."count" AS "count", "source"."name" AS "name", "source"."count" AS "count_2", ("source"."count" * 1.5) AS "a" FROM (SELECT "marketing_campaign__via__campa"."name" AS "name", count(*) AS "count" FROM "public"."event_event"
LEFT JOIN "public"."event_event" "Event Event - Source Event" ON "public"."event_event"."source_event_id" = "Event Event - Source Event"."id" LEFT JOIN "public"."marketing_campaign" "marketing_campaign__via__campa" ON "public"."event_event"."campaign_id" = "marketing_campaign__via__campa"."id"
WHERE "public"."event_event"."status" = 'Queued'
GROUP BY "marketing_campaign__via__campa"."name"
ORDER BY "marketing_campaign__via__campa"."name" ASC) "source") "source"
union all
SELECT marketing_campaign.name,
cast(sum((event_event.status='Opt-in')::int) as decimal) / nullif(sum((event_event.status='Sent')::int), 0)* 100 as "Opt-in Rate (Sent)"
FROM event_event
JOIN marketing_campaign ON event_event.campaign_id = marketing_campaign.id
WHERE marketing_campaign.is_archived=false [[AND {{date_created}}]]
GROUP BY marketing_campaign.name
LIMIT 1048576
而不是 union all 你需要加入名称列上的 table 然后 select 第二列分别来自两个 tables .我正在考虑名称列与两个 table 相同的事实。如果在一个 table 中存在任何名称而在另一个中不存在,则结果中不会显示该名称
select t1.name,t1.count ,t2."Opt-in Rate (Sent)" ,t1.count*t2."Opt-in Rate (Sent)" as predicted
from (
SELECT "source"."name" AS "name", "source"."count" AS "count"
FROM (SELECT "source"."count" AS "count", "source"."name" AS "name", "source"."count" AS "count_2", ("source"."count" * 1.5) AS "a" FROM (SELECT "marketing_campaign__via__campa"."name" AS "name", count(*) AS "count" FROM "public"."event_event"
LEFT JOIN "public"."event_event" "Event Event - Source Event" ON "public"."event_event"."source_event_id" = "Event Event - Source Event"."id" LEFT JOIN "public"."marketing_campaign" "marketing_campaign__via__campa" ON "public"."event_event"."campaign_id" = "marketing_campaign__via__campa"."id"
WHERE "public"."event_event"."status" = 'Queued'
GROUP BY "marketing_campaign__via__campa"."name"
ORDER BY "marketing_campaign__via__campa"."name" ASC) "source") "source") t1 inner join
(
SELECT marketing_campaign.name,
cast(sum((event_event.status='Opt-in')::int) as decimal) / nullif(sum((event_event.status='Sent')::int), 0)* 100 as "Opt-in Rate (Sent)"
FROM event_event
JOIN marketing_campaign ON event_event.campaign_id = marketing_campaign.id
WHERE marketing_campaign.is_archived=false [[AND {{date_created}}]]
GROUP BY marketing_campaign.name
)t2 on t1.name=t2.name
LIMIT 1048576
我正在元数据库中进行 SQL 数据库查询。我有两个单独的查询,我希望将它们输出为两个单独的列,按名称排序。在执行 union 之后,它似乎将所有值都放入一列中以复制名称。实现两列输出(每个查询一个)的最佳方法是什么?
SELECT "source"."name" AS "name", "source"."count" AS "count"
FROM (SELECT "source"."count" AS "count", "source"."name" AS "name", "source"."count" AS "count_2", ("source"."count" * 1.5) AS "a" FROM (SELECT "marketing_campaign__via__campa"."name" AS "name", count(*) AS "count" FROM "public"."event_event"
LEFT JOIN "public"."event_event" "Event Event - Source Event" ON "public"."event_event"."source_event_id" = "Event Event - Source Event"."id" LEFT JOIN "public"."marketing_campaign" "marketing_campaign__via__campa" ON "public"."event_event"."campaign_id" = "marketing_campaign__via__campa"."id"
WHERE "public"."event_event"."status" = 'Queued'
GROUP BY "marketing_campaign__via__campa"."name"
ORDER BY "marketing_campaign__via__campa"."name" ASC) "source") "source"
union all
SELECT marketing_campaign.name,
cast(sum((event_event.status='Opt-in')::int) as decimal) / nullif(sum((event_event.status='Sent')::int), 0)* 100 as "Opt-in Rate (Sent)"
FROM event_event
JOIN marketing_campaign ON event_event.campaign_id = marketing_campaign.id
WHERE marketing_campaign.is_archived=false [[AND {{date_created}}]]
GROUP BY marketing_campaign.name
LIMIT 1048576
而不是 union all 你需要加入名称列上的 table 然后 select 第二列分别来自两个 tables .我正在考虑名称列与两个 table 相同的事实。如果在一个 table 中存在任何名称而在另一个中不存在,则结果中不会显示该名称
select t1.name,t1.count ,t2."Opt-in Rate (Sent)" ,t1.count*t2."Opt-in Rate (Sent)" as predicted
from (
SELECT "source"."name" AS "name", "source"."count" AS "count"
FROM (SELECT "source"."count" AS "count", "source"."name" AS "name", "source"."count" AS "count_2", ("source"."count" * 1.5) AS "a" FROM (SELECT "marketing_campaign__via__campa"."name" AS "name", count(*) AS "count" FROM "public"."event_event"
LEFT JOIN "public"."event_event" "Event Event - Source Event" ON "public"."event_event"."source_event_id" = "Event Event - Source Event"."id" LEFT JOIN "public"."marketing_campaign" "marketing_campaign__via__campa" ON "public"."event_event"."campaign_id" = "marketing_campaign__via__campa"."id"
WHERE "public"."event_event"."status" = 'Queued'
GROUP BY "marketing_campaign__via__campa"."name"
ORDER BY "marketing_campaign__via__campa"."name" ASC) "source") "source") t1 inner join
(
SELECT marketing_campaign.name,
cast(sum((event_event.status='Opt-in')::int) as decimal) / nullif(sum((event_event.status='Sent')::int), 0)* 100 as "Opt-in Rate (Sent)"
FROM event_event
JOIN marketing_campaign ON event_event.campaign_id = marketing_campaign.id
WHERE marketing_campaign.is_archived=false [[AND {{date_created}}]]
GROUP BY marketing_campaign.name
)t2 on t1.name=t2.name
LIMIT 1048576