如果我无法遍历 Match.object，我应该怎么做？

Question

我正在为一项功能苦苦挣扎。它是 scraping outlook 的一个函数，它找到一个特定的单词“Number1”并选择这个单词附近的数字。其中一些数字以“0”开头，我想将其更改为“32”而不是“0”并保存为列表。

但我无法遍历 Match.object 并且我不知道如何实现我的目标的任何其他可能性。

这是我试过的：

def get_number(file):
   try:
       body = file.body
       matches = re.finditer(r"Number1:\s(.*)$", body, re.MULTILINE)
       list_of_numbers = []
       for match in matches:
             for i in match.group(1):
                  if i[0] == 0:
                      list_of_numbers.append("32" + i[1:])
        return list_of_numbers
      

   except Exception as e:
       print(e)

这是典型电子邮件的示例：

Subject: Test1

Hi,
You got a new answer from user Alex. 

Code: alex123fj
Number1: 0611111111
Number2: 1020
Number3: 3032

Answer 1

您的正则表达式只会找到 Number1: ..，但可能有多个数字以 0 开头，如您在问题中所述。以下是获得所需输出的方法：

import re

body = """
Subject: Test1

Hi,
You got a new answer from user Alex. 

Code: alex123fj
Number1: 0611111111
Number2: 1020
Number3: 3032
"""

matches = re.findall(r"^Number.*$", body, re.MULTILINE)
# -> [Number1: 0611111111, Number2: 1020, Number3: 3032]

# getting only numbers from that list
nums = [ch for match in matches for ch in match.split() if ch.isdigit()]
# -> ['0611111111', '1020', '3032']

list_of_numbers = ['32' + i[1:] for i in nums if i[0] == '0']
# -> ['32611111111']

如果我无法遍历 Match.object，我应该怎么做？

If I could not iterate through Match.object, what should I do instead?

python

outlook

match