尝试连接到 Codeigniter 中的非默认数据库时出错

Error when attempting to connect to a non-default database in Codeigniter

这是我尝试连接的数据库的数据库配置。对于这个特定的模型是不同的。

$db['campaignsDB']['hostname'] = 'localhost';
$db['campaignsDB']['username'] = 'root';
$db['campaignsDB']['password'] = '';
$db['campaignsDB']['database'] = 'sf_campaigns';
$db['campaignsDB']['dbdriver'] = 'mysql';
$db['campaignsDB']['dbprefix'] = '';
$db['campaignsDB']['pconnect'] = TRUE;
$db['campaignsDB']['db_debug'] = TRUE;
$db['campaignsDB']['cache_on'] = FALSE;
$db['campaignsDB']['cachedir'] = '';
$db['campaignsDB']['char_set'] = 'utf8';
$db['campaignsDB']['dbcollat'] = 'utf8_general_ci';
$db['campaignsDB']['swap_pre'] = '';
$db['campaignsDB']['autoinit'] = TRUE;
$db['campaignsDB']['stricton'] = FALSE;

我已经创建了一个 crud_model 并且我确定函数编写正确,但我将包括相关部分...

class CRUD_model extends CI_Model
{
    protected $database = null;
    protected $_table = null;
    protected $_primary_key = null;

    public function __construct()
    {
        parent::__construct();
        $this->load->database($this->database, TRUE);
    }

我遇到的问题如下:

我创建了一个campaigns_model...

class Campaigns_model extends CRUD_model
{
    protected $database = "campaignsDB"; //DEFINE database
    protected $_table = "camp_forminfo";
    protected $_primary_key = "form_id";

    public function __construct()
    {
        parent::__construct();
    }
}

现在我在长时间中断后回到面向对象编程,所以我可能在这里遗漏了一些重要的部分,但我可以通过定义一个基变量来发誓 class在派生的 class 中,当我尝试使用基本 class' 方法时,它会被定义。我尝试在我的控制器中使用 CRUD_model 的插入功能...

首先我加载 campaigns_model...

class Campaigns extends MY_Controller
{
    private $layout = "";
    private $content = "";

    public function __construct()
    {
        parent::__construct($this->layout);
        $this->load->model('campaigns_model');  
    }

然后我在我的控制器函数中使用它...

public function saveForm()
{
    $this->campaigns_model->insert([
        'form_name' => $this->input->post('form_name'),
        'form_leads' => $this->input->post('form_leads'),
        'form_content' => $this->input->post('form_content'),
        'form_template' => $this->input->post('form_template')  
    ]);
}

我收到以下错误:

An Error Was Encountered

You have not selected a database type to connect to.

我可能是错的,但这是我在双数据库应用程序中的做法:

class CRUD_model extends CI_Model{
    protected $database = null;
    protected $_table = null;
    protected $_primary_key = null;

    public function __construct() {
        parent::__construct();
        $this->db = $this->load->database($this->database, true);
    }

奇怪的是,我能够通过对我的 CRUD_model 代码稍作修改来使这一切正常工作。

通过改变这个...

class CRUD_model extends CI_Model
{
    protected $database = null;
    protected $_table = null;
    protected $_primary_key = null;

public function __construct()
{
    parent::__construct();
    $this->load->database($this->database, TRUE);
}

为此...

class CRUD_model extends CI_Model
{
    protected $database = null;
    protected $_table = null;
    protected $_primary_key = null;

public function __construct()
{
    parent::__construct();
    $this->load->database("".$this->database."", TRUE);
}

它起作用了...通过强制将该变量解释为它起作用的字符串。为什么会这样,我还没学会,谁能分享一下?