删除右括号第一次出现的字符串

Question

我有一个如下所示的文件：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

我想去掉日期和时间戳（例如，[2021-03-08 22:55:53.937]）。为此，我尝试使用以下 sed 命令：

sed -i '/^\[2021-/s/^.*\]\ //1' output.txt

但是，时间戳右侧的 [info] 或 [error] 括号也会被删除：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

当我尝试时

sed -i '/^\[2021/s/[^\]]*//' output.txt

删除第一个左括号而不是第一个右括号：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

并尝试

sed -i '/^\[2021/s/^[^\]]*\]//' output.txt

没有变化。我不确定如何解决这个问题。我尝试了类似帖子中推荐的一些东西，但没有成功。

注意：这不是的重复，因为这里的问题不同：只匹配字符串开头和第一个 [=] 之间的子字符串20=] + space 如果该行以某个前缀开头。

sed replace a word at a line which begins with a specific pattern using 没有解释如何获取以特殊字符开头的行，然后匹配从开始到第一个 ] + space.[=24= 的字符串]

Answer 1

您可以使用

sed -i '/^\[2021-/s/^[^]]*] //' file

这里，

/^\[2021-/ - 查找以 [2021-
s/^[^]]*] // - 匹配除 ] 之外的任何零个或多个字符，从字符串的开头到第一个 ] 然后是 space 并删除这些匹配（因为 RHS 为空）。

注意 [^]] 是一个 否定括号表达式 匹配除 ] 之外的任何字符。由于括号表达式不支持正则表达式转义序列，] 需要是括号表达式中的第一个字符，您不能在括号表达式中的任意位置使用 \]。

见an online demo:

s='[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR'
sed '/^\[2021-/s/^[^]]*] //' <<< "$s"

输出：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

删除右括号第一次出现的字符串

Deleting a string upto first occurrence of right bracket

regex

posix

replace

sed